如何将移动构造函数与二维数组 (**) 一起使用？

可能是我错误地编码了我的类，但是当我使用移动构造函数而不是复制 cotr（作为重载之一，而不是准确地说）时，我的程序崩溃了：

例如：

class Sample
{
    int a;
    int **b;
    //constructor declarations
}

在 .cpp 文件中：

Sample::Sample(Sample &&other)
    : a(a), b(b)
{
    for (int i = 0; i < a; i++)
        other.b[i] = nullptr;
    other.b = nullptr;
    other.a = 0;
}

如何解决这个问题？

以下是移动值的方法：

#include <utility>
#include <iostream>

class Sample
{
    int a;
    int **b;
public:
    Sample(int a, int** b) : a{a}, b{b} {}
    Sample(Sample &&other);
    // still missing a destructor that will get rid of the new'd ints
    void print();
};

Sample::Sample(Sample &&other)
    : a(other.a), b(other.b)
{
    //for(int i = 0; i < a; i++)
    //  other.b[i] = nullptr; // this should not be done, the new b has a pointer to these values
    other.b = nullptr;
    other.a = 0;
}

void Sample::print()
{
    if(a == 0 && b == nullptr)
        std::cout << "this object is empty!";
    for(size_t i{0}; i < a; ++i) {
        std::cout << *b[i] << " ";
    }
    std::cout << '\n';
}

int main()
{
    Sample s{5,{new int*[5]{new int{0}, new int{1}, new int{2}, new int{3}, new int{4}}}};
    auto c{std::move(s)};
    // c now has c.b as a pointer an array of pointers
    s.print();
    c.print();
    return 0;
}