我目前有一个 MQTT 代码，可以订阅主题、打印收到的消息，然后向新主题发布进一步的指令。这订阅/打印在一个 Goroutine 中完成，并且出版是在另一个 Goroutine 中完成的。这是我的代码：
var wg, pg sync.WaitGroup
// All messages are handled here - printing published messages and publishing new messages
var f MQTT.MessageHandler = func(client MQTT.Client, msg MQTT.Message) {
wg.Add(1)
pg.Add(1)
go func() {
defer wg.Done()
fmt.Printf("%s\n", msg.Payload())
//fmt.Println(os.Getpid())
}()
go func(){
defer pg.Done()
message := ""
//Changing configurations
if strings.Contains(string(msg.Payload()), "arduinoLED") == true {
message = fmt.Sprintf("change configuration")
}
if strings.Contains(string(msg.Payload()), "NAME CHANGED") == true{
message = fmt.Sprintf("change back")
}
// Publish further instructions to "sensor/instruction"
token := client.Publish("sensor/instruction", 0, false, message)
//fmt.Println(os.Getpid())
token.Wait()
}()
}
func main() {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt, syscall.SIGTERM)
opts := MQTT.NewClientOptions().AddBroker("tcp://test.mosquitto.org:1883")
opts.SetDefaultPublishHandler(f)
// Topic to subscribe to for sensor data
topic := "sensor/data"
opts.OnConnect = func(c MQTT.Client) {
if token := c.Subscribe(topic, 0, f); token.Wait() && token.Error() != nil {
panic(token.Error())
}
}
// Creating new client
client := MQTT.NewClient(opts)
if token := client.Connect(); token.Wait() && token.Error() != nil {
panic(token.Error())
} else {
fmt.Printf("Connected to server\n")
}
wg.Wait()
pg.Wait()
<-c
}
被注释掉的os.Getpid()行是检查我正在哪个进程上运行该 Goroutine。现在它们都显示相同的数字（这意味着两者都在同一进程上运行？）。
我的问题是：我怎样才能运行这两个 Goroutine单独的进程？有办法吗？
Edit:如果这不能完成，我想使用编写此代码channels。这是我的代码：
var f MQTT.MessageHandler = func(client MQTT.Client, msg MQTT.Message) {
sensorData := make(chan []byte)
wg.Add(1)
pg.Add(1)
go func() {
defer wg.Done()
//fmt.Printf("%s\n", msg.Payload())
sensorData <- string(msg.Payload())
fmt.Println(<-sensorData) //currently not printing anything
}()
go func(){
defer pg.Done()
message := ""
//Changing configurations
if strings.Contains(<-sensorData, "arduinoLED") == true{
message = fmt.Sprintf("change configuration")
}
if strings.Contains(<-sensorData, "NAME CHANGED") == true{
message = fmt.Sprintf("change back")
}
// Publish further instructions to "sensor/instruction"
token := client.Publish("sensor/instruction", 0, false, message)
token.Wait()
}()
}
但是，我无法使用通道打印任何数据。我究竟做错了什么？
