从网络摄像头录制视频流并将 blob 上传到服务器

所以我有一个网站可以记录来自用户网络摄像头的视频流并将其转换为 blob 使用getUserMedia()。我现在想将此 blob 发送到服务器，以便可以保存和处理视频。我在通过 ajax 发送 blob 文件时遇到问题，我尝试过使用 formData + XMLHttpRequest() 方法以及纯 ajax。对于我的应用程序来说，用户可以录制视频并立即将该视频发送到我的服务器是必要的。

任何帮助将不胜感激。

so HTML:

    <div class="demo">
    <video id="preview" autoplay width="400" height="300"></video>
    <video id="recording" width="400" height="300" style="display:none;" controls></video>

    <div class="progress">
        <div class="progress-bar"></div>
        <span>01:00</span>
    </div>
    <button class="record">Record</button>
    <button class="upload">Upload</button>
</div>

相关JS函数：

function captureVideo () {
    const preview = document.querySelector('video#preview');
    const recording = document.querySelector('video#recording');
    navigator.mediaDevices.getUserMedia({video: true}).then((stream) => {
        preview.srcObject = stream;
        preview.captureStream = preview.captureStream || preview.mozCaptureStream;
        return new Promise(resolve => preview.onplaying = resolve);
    }).then(() => {
        let recorder = new MediaRecorder(preview.captureStream());
        let data = [];

        recorder.ondataavailable = event => data.push(event.data);
        recorder.start();
        log(recorder.state + " for " + (60000/1000) + " seconds...");

        let stopped = new Promise((resolve, reject) => {
            recorder.onstop = resolve;
            recorder.onerror = event => reject(event.name);
        });

        $('button.stop').click(function () {
            recorder.stop();
        });

        return Promise.all([ stopped ]).then(() => data);
    }).then ((recordedChunks) => {
        let recordedBlob = new Blob(recordedChunks, {
            type: "video/webm"
        });
        recording.src = URL.createObjectURL(recordedBlob);
        $('#preview').hide();
        $('#recording').show();
        log("Successfully recorded " + recordedBlob.size + " bytes of " +
            recordedBlob.type + " media.");
        $('button.upload').click(function() {
            sendVideoToAPI(recordedBlob);
        });
    }).catch(log);
}
function sendVideoToAPI (blob) {

    let fd = new FormData();
    let file = new File([blob], 'recording');

    fd.append('data', file);
    console.log(fd); // test to see if appending form data would work, it didn't this is completely empty. 


    let form = new FormData();
    let request = new XMLHttpRequest();
    form.append("file",file);
    request.open("POST",  "/demo/upload", true);
    request.send(form); // hits the route but doesn't send the file
    console.log(request.response) // returns nothing

    // I have also tried this method which hits the route and gets a response however the file is not present in the request when it hits the server. 
    // $.ajax({
    //     url: Routing.generate('upload'),
    //     data: file,
    //     contentType: false,
    //     processData: false,
    //     error: function (res) {
    //         console.log(res);
    //     },
    //     success: function(res) {
    //         console.log(res);
    //     }
    // });
}

您正在发送 ajax 请求，在 send() 命令之后不会立即收到响应。您可以使用请求 onload 事件访问响应值

request.onload = function () {
            if (request.readyState === request.DONE) {
                if (request.status === 200) {
                    console.log(request.response);
                }
            }
        };