JavaScript - 返回两个对象之间的差异？

有人可以告诉我在比较这样的数据时如何返回新数据吗？使用普通 JavaScript。

{
    "48": "{\"sid\":\"48\",\"name\":\"title 1\"}",
    "77": "{\"sid\":\"77\",\"name\":\"The blahblah title\"}"
}

与此相比

{
    "48": "{\"sid\":\"48\",\"name\":\"title 1\"}",
    "77": "{\"sid\":\"77\",\"name\":\"The blahblah title\"}",
    "83": "{\"sid\":\"83\",\"name\":\"The blahblah derp\"}",
    "87": "{\"sid\":\"87\",\"name\":\"The derpy title 4\"}"
}

它应该只返回差异。

{
    "83": "{\"sid\":\"83\",\"name\":\"The blahblah derp\"}",
    "87": "{\"sid\":\"87\",\"name\":\"The derpy title 4\"}"
}

您可以使用对象.keys() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/keys and 数组.includes() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes要做到这一点。

var data = {
  "48": "{\"sid\":\"48\",\"name\":\"title 1\"}",
  "77": "{\"sid\":\"77\",\"name\":\"The blahblah title\"}",
  "83": "{\"sid\":\"83\",\"name\":\"The blahblah derp\"}",
  "87": "{\"sid\":\"87\",\"name\":\"The derpy title 4\"}"
};

var obj1 = {
  "48": "{\"sid\":\"48\",\"name\":\"title 1\"}",
  "77": "{\"sid\":\"77\",\"name\":\"The blahblah title\"}"
};

var result = {};
var keys = Object.keys(obj1);

for (var key in data) {
 if (!keys.includes(key)) {
  result[key] = data[key];
 }
}

console.log(result);