我有一个字符串:
var text = @"
I have a long string with a load of words,
and it includes new lines and non-letter characters.
I want to remove all of them and split this text to have one word per line, then I can count how many of each word exist."
删除所有非字母字符,然后将每个单词拆分到新行以便我可以存储并计算每个单词有多少个,最好的方法是什么?
var words = text.Split(' ');
foreach(var word in words)
{
word.Trim(',','.','-');
}
我尝试过各种事情,例如text.Replace(characters)
with whitespace
然后分裂。我尝试过正则表达式(我不想使用它)。
我还尝试使用 StringBuilder 类从文本(字符串)中获取字符,并且仅在字符是字母 a-z / A-Z 时才附加该字符。
还尝试调用 sb.Replace 或 sb.Remove 在将它们存储在字典中之前不需要的字符。但我似乎仍然得到了我不想要的角色?
我所做的一切尝试,似乎至少有一个我不想要的角色,而且不太明白为什么它不起作用。
Thanks!
使用没有 RegEx 和 Linq 的扩展方法
static public class StringHelper
{
static public Dictionary<string, int> CountDistinctWords(this string text)
{
string str = text.Replace(Environment.NewLine, " ");
var words = new Dictionary<string, int>();
var builder = new StringBuilder();
char charCurrent;
Action processBuilder = () =>
{
var word = builder.ToString();
if ( !string.IsNullOrEmpty(word) )
if ( !words.ContainsKey(word) )
words.Add(word, 1);
else
words[word]++;
};
for ( int index = 0; index < str.Length; index++ )
{
charCurrent = str[index];
if ( char.IsLetter(charCurrent) )
builder.Append(charCurrent);
else
if ( !char.IsNumber(charCurrent) )
charCurrent = ' ';
if ( char.IsWhiteSpace(charCurrent) )
{
processBuilder();
builder.Clear();
}
}
processBuilder();
return words;
}
}
它解析所有字符,拒绝所有非字母,同时创建每个单词的字典,并计算出现次数。
Test
var result = text.CountDistinctWords();
Console.WriteLine($"Found {result.Count()} distinct words:");
Console.WriteLine();
foreach ( var item in result )
Console.WriteLine($"{item.Key}: {item.Value}");
样品结果
Found 36 distinct words:
I: 3
have: 2
a: 2
long: 1
string: 1
with: 1
load: 1
of: 3
words: 1
and: 3
it: 1
includes: 1
new: 1
lines: 1
non: 1
letter: 1
characters: 1
want: 1
to: 2
remove: 1
all: 1
them: 1
split: 1
this: 1
text: 1
one: 1
word: 2
per: 1
line: 1
then: 1
can: 1
count: 1
how: 1
many: 1
each: 1
exist: 1
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