C++ 随机猜数字游戏

我必须编写一个程序来运行随机猜谜游戏。游戏的数字是从 1 到 100，猜测者可以尝试 20 次，最后应该被问是否愿意再玩一次。如果猜测者高或低，还必须有多种打印输出选项。我已经完成了程序的一部分，我知道我仍然需要添加其他打印输出选项，但现在我的问题是，当我尝试运行我所拥有的内容时，它说成功，但随后出现一个错误，指出变量“ number”正在使用而未初始化。我不知道该怎么做才能让它明显初始化。 （我是 C++ 新手）我已经更新了我的程序，现在遇到了不同的问题。我的程序运行，但如果猜测值低于它打印的数字，则打印太高，再试一次，太低，再试一次，但当数字太高时，它只会打印太高，再试一次。我还注意到，当用户选择再次玩游戏时，尝试计数器不会随游戏重置。最后一件事是，当他们获胜、失败并被要求玩另一场游戏时，我必须添加更多消息，并且我必须使用随机数在其中进行选择。所以任何关于最佳路线的建议都会很棒

#include <iostream>
#include <iomanip> 
#include <ctime>
using namespace std;
char chr;

int main()
{
srand(time(NULL));                                           //the function that generates random numbers
int number=rand()%100+1;                                     //the range of the random numbers
int guess;                                                   //The guess is stored here
int tries=0;                                                 //The number of tries stored here
   char answer;                                                 //The answer to the question is stored here
answer='y';                  

while(answer=='y'||answer=='Y') 
{
    while (tries<=20 && answer=='y'|| answer=='Y')
    {
    cout<<"Enter a number between 1 and 100 "<<endl;          //The user is asked for a guess
    cin>>guess;                                               //The guess is stored here
    tries++;                                                 //Adding a number for every try
    if(guess==0||guess>100)                                  //If statement that produces an error message if user enters a number out of the peramiters
    {
     cout<<"This is not an option try again"<<endl;          //Error message
    }

    if(tries<20)                                            
    cout<<"Tries left: "<<(20-tries)<<endl;                   //Output to let the user know how many guess they have left

    if(number<guess);                                         //if the guess is to high
    cout<<"Too high try again"<<endl;                         //This message prints if guess it to high

    if(number>guess)                                          //if the guess is to low
    cout<<"Too low try again"<<endl;                          //This message prints if the guess is to low

    if(number==guess)                                          //If the user guesses the number
    {
     cout<<"Congratualtions!! "<<endl;                          //Message printed out if the user guesses correctly
     cout<<"You got the right number in "<<tries<<" tries"<<endl;  //Lets the user know how many guess they used
     answer = 'n';
    }
    if(tries >= 20)                                               //If the user uses all their guesses
    {
    cout << "You've run out of tries!"<<endl;                      //The message that prints when a user is out of guesses
    answer='n';
    }
    if(answer=='n')
    {
     cout<<"Would you like to play again?  Enter Y/N"<<endl;       //asking if play would like to play again
     cin>>answer;                                                  //Store users answer
     if (answer=='N'|| answer=='n')                                //if the user says no
     cout<<"Thanks for playing!"<<endl;                            //This message prints out if they choose not to play again

    else
        number=rand()%100+1;                                        //This starts the game over if they choose to play again
    }

    }
    }

cin>>chr;
    return 0;

}

[编辑：添加强制转换以消除编译器警告。]

正如吉姆·罗兹（Jim Rhodes）在评论中所说，问题在于这条线

srand(number>0);

srand() http://www.cplusplus.com/reference/cstdlib/srand/用于初始化随机数生成器，因此用它来调用它是没有意义的number>0，或者甚至与number根本不。它需要一个“种子”值，每次运行程序时该值都应该不同。获取此类种子的常见方法是使用系统时间：

srand(static_cast<unsigned int>(time(NULL)));

你可能需要#include要访问的另一个标头time() http://www.cplusplus.com/reference/ctime/time/.