以下是我的 xml 文件。我必须为每个页面和每个类型获取以逗号分隔的字符串提到的字段。请帮助了解如何继续使用 Linq
示例:如果我想为“page1”定义“Type = customFields”,则必须以逗号分隔输出
项目ID、员工ID、员工姓名、hasExpiration 等
<Pages>
<Page Name="Page1" >
<Type TypeID="customfields">
<Field>ProjectID</Field>
<Field>EmployeeID</Field>
<Field>EmployeeName</Field>
<Field>HasExpiration</Field>
<Field>EndDate</Field>
</Type>
<Type TypeID="Directfields">
<Field>ProjectID</Field>
<Field>EmployeeID</Field>
<Field>EmployeeName</Field>
<Field>HasExpiration</Field>
<Field>EndDate</Field>
<Field>IsInUpdateMode</Field>
<Field>TimesheetSpendLimit</Field>
</Type>
</Page>
<Page Name="Page2" >
<Type TypeID="customfields">
<Field>ProjectID</Field>
<Field>EmployeeID</Field>
<Field>EmployeeName</Field>
<Field>HasExpiration</Field>
<Field>EndDate</Field>
<Field>IsInUpdateMode</Field>
<Field>TimesheetSpendLimit</Field>
</Type>
<Type TypeID="Directfields">
<Field>ProjectID</Field>
<Field>EmployeeID</Field>
<Field>EmployeeName</Field>
<Field>HasExpiration</Field>
<Field>EndDate</Field>
<Field>IsInUpdateMode</Field>
<Field>TimesheetSpendLimit</Field>
</Type>
</Page>
</Pages>
你可以这样做:
var Result = from a in element.Descendants("Page")
from b in a.Descendants("Type")
select new
{
Page = a.Attribute("Name").Value,
Type = b.Attribute("TypeID").Value,
Fields = String.Join(",", b.Elements("Field").Select(x => x.Value))
};
foreach (var item in Result)
{
Console.WriteLine(String.Format("Page = {0}:Type={1}:Fields:{2}", item.Page, item.Type, item.Fields));
}
工作小提琴 https://dotnetfiddle.net/sGei6d
检查我的这篇博客文章 http://developmentpassion.blogspot.com/2014/09/how-to-deserialize-xml-using-linq.html以及更多。
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