insert all
into REGIONS (select :REGION_ID,REGION_NAME from REGION where REGION_ID = 4)
into JOBS (select :JOB_ID,JOB_TITLE,MIN_SALARY,MAX_SALARY where JOB_ID = 'ST_CLERK')
select * from DUAL;
以上全部插入语法上不正确。你必须提到VALUES关键字,以及列出所需的列您想要从表中选择要插入的行。
正确的语法是:
INSERT ALL
INTO REGIONS VALUES
(
REGION_ID,
REGION_NAME
)
INTO JOBS VALUES
(
JOB_ID,
JOB_TITLE,
MIN_SALARY,
MAX_SALARY
)
SELECT REGION_ID,
REGION_NAME,
JOB_ID,
JOB_TITLE,
MIN_SALARY,
MAX_SALARY
FROM region, jobs
WHERE region.column=job.column --> Jon with the required key
AND ...; --> Put the required filter conditions
目标表中具有相同的列。
SQL> CREATE TABLE tab1(a NUMBER, b varchar2(20));
Table created.
SQL> CREATE TABLE tab2(a NUMBER, b varchar2(20));
Table created.
SQL>
SQL> INSERT ALL
2 INTO tab1(A, b) VALUES(empno, ename)
3 INTO tab2(A, b)VALUES(empno, ename)
4 SELECT empno, ename FROM emp;
28 rows created.
SQL>
因此,所有行都插入到表中tab1 and tab2分别。让我们来看看:
SQL> SELECT * FROM tab1;
A B
---------- --------------------
7369 SMITH
7499 ALLEN
7521 WARD
7566 JONES
7654 MARTIN
7698 BLAKE
7782 CLARK
7788 SCOTT
7839 KING
7844 TURNER
7876 ADAMS
7900 JAMES
7902 FORD
7934 MILLER
14 rows selected.
SQL> SELECT * FROM tab2;
A B
---------- --------------------
7369 SMITH
7499 ALLEN
7521 WARD
7566 JONES
7654 MARTIN
7698 BLAKE
7782 CLARK
7788 SCOTT
7839 KING
7844 TURNER
7876 ADAMS
7900 JAMES
7902 FORD
7934 MILLER
14 rows selected.
SQL>
目标表中具有不同的列。
SQL> CREATE TABLE tab1(a NUMBER);
Table created.
SQL> CREATE TABLE tab2(b varchar2(20));
Table created.
SQL>
SQL> INSERT ALL
2 INTO tab1(A) VALUES(empno)
3 INTO tab2(b)VALUES(ename)
4 SELECT empno, ename FROM emp;
28 rows created.
让我们来看看:
SQL> SELECT * FROM tab1;
A
----------
7369
7499
7521
7566
7654
7698
7782
7788
7839
7844
7876
7900
7902
7934
14 rows selected.
SQL> SELECT * FROM tab2;
B
--------------------
SMITH
ALLEN
WARD
JONES
MARTIN
BLAKE
CLARK
SCOTT
KING
TURNER
ADAMS
JAMES
FORD
MILLER
14 rows selected.
SQL>
目标表中的列不同,源表中的列不同
SQL> CREATE TABLE tab1(A VARCHAR2(20));
Table created.
SQL> CREATE TABLE tab2(b NUMBER);
Table created.
SQL>
SQL> INSERT ALL
2 INTO tab1(A) VALUES(ename)
3 INTO tab2(b)VALUES(deptno)
4 SELECT e.ename ename, d.deptno deptno FROM emp e, dept d
5 where e.deptno = d.deptno;
28 rows created.
SQL>
让我们来看看:
SQL> SELECT * FROM tab1;
A
--------------------
SMITH
ALLEN
WARD
JONES
MARTIN
BLAKE
CLARK
SCOTT
KING
TURNER
ADAMS
JAMES
FORD
MILLER
14 rows selected.
SQL> SELECT * FROM tab2;
B
----------
20
30
30
20
30
30
10
20
10
30
20
30
20
10
14 rows selected.
SQL>