你知道 PHP 的任何严格等效的实现吗相似文本 https://www.php.net/manual/en/function.similar-text.phpJava 中的函数?
这是我在java中的实现:
package comwebndesignserver.server;
import android.util.Log;
/*
*
* DenPashkov 2012
* http://www.facebook.com/pashkovdenis
* * PhP Similar String Implementation
* 30.07.2012
*
*/
public class SimilarString {
private String string = "" ;
private String string2 = "";
public int procent = 0 ;
private int position1 =0 ;
private int position2 =0;
// Similar String
public SimilarString(String str1, String str2){
this.string = str1.toLowerCase();
this.string2 = str2.toLowerCase();
}
public SimilarString() {
}
// Set string
public SimilarString setString(String str1, String str2){
this.string = str1.toLowerCase();
this.string2 = str2.toLowerCase();
return this ;
}
//get Similar
public int similar(){
string= string.trim() ;
string2= string2.trim();
int len_str1 = string.length() ;
int len_str2 = string2.length() ;
int max= 0;
if (string.length()>1 && string2.length()>1 ){
// iterate
for (int p=0 ; p<=len_str1; p++){
for (int q=0 ; q<=len_str2; q++){
for(int l=0 ; (p + l < len_str1) && (q + l < len_str2) && (string.charAt(l) == string2.charAt(l)); l++){
if (l>max){
max=l ;
position1 = p ;
position2 = q;
}
}
}
}
//sim * 200.0 / (t1_len + t2_len)
this.procent = max * 200 / ((string.length()) + (string2.length()) - (max) + (position2 - position1) ) - (max*string.length() ) ;
if (procent>100) procent = 100;
if (procent<0) procent = 0;
}
return this.procent ;
}
}
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