与php中的另一个数组合并后如何从数组中删除重复元素？

我正在尝试编写程序来计算指定开始日期后的接下来 20 个日期，然后从 20 个日期中排除周末 &Holidays(Array holidays('2016-12-13',2016-12-24))以及结果数组，其中仅包含除周六和周日之外的工作日，在假期过后的结果数组中array(Eg:- holidays('2016-12-13',2016-12-24)))，它必须从结果数组中排除。 IE;

我想要下面提到的预期输出

.

    <?php 
$Date=array('2016-12-01');
echo "\n <br />Start Date:-" . $Date[0] . ""; 

                            /*Code For Generating Next 20 Dates Starts*/
//$start = strtotime($s_row['schedule_start_date']);

$start = strtotime('2016-12-01');
$dates=array();
for($i = 0; $i<20; $i++)
{
    array_push($dates,date('Y-m-d', strtotime("+$i day", $start)));
}
echo "\n <br /> Array Of next 20 Days/dates of Given:-";
print_r($dates);

$start=array();
$start=$dates;                            /*Code For Generating Next 20 Dates Ends*/
$result=array();

$start = strtotime(array_values($Date)[0]);
//$end = strtotime(array_values($Date)[30]);
$result = array();
$begin = new DateTime( '2016-12-01' );
$end = new DateTime( '' );
//$end = $end->modify( '+1 day' ); 

$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);

foreach($daterange as $date)
{
   //echo $date->format("Y-m-d") . "<br>";
   if (date('N', $start) <= 5)     /* 'N' number days 1 (mon) to 7 (sun) */
                                    /*5 weekday */   
   {
        $current = date('Y-m-d', $start);     //m/d/Y
        $result[$current] = '';

    }
    $start += 86400;
    //echo "Days Without Sat Sun".$result[date($date->format("Y-m-d"))];
      //echo "Days Without Sat Sun".$result2[date($current->format("Y-m-d"))];  

} 
echo " \n <br /> Dates Without Weekends LIKE (Excluding Saturday & Sunday):-";
print_r($result);



        /*For Holiday*/
$FinalArray = array();        
$holidays = array(
  '2016-12-13',
  '2016-12-24',
);
echo " \n <br /> Given Holiday Dates Are:-";
print_r($holidays);



$a1 = $result;
 $a2 = $holidays;
 $array =  array_diff(array_merge($a1,$a2),array_intersect($a1,$a2));

echo "\n <br /> Output:-";
 print_r($array);

?>

它给出的输出为：- Array ( [2016-12-01] => [2016-12-02] => [2016-12-05] => [2016-12-06] => [2016-12-07] => [2016-12-08] => [2016-12-09] => [2016-12-12] => [2016-12-13] => [2016-12-14] => [2016-12-15] => [2016-12-16] => [2016-12-19] => [2016-12-20] => [2016-12-21] => [2016-12-22] => [2016-12-23] => [0] => 2016-12-13 [1] => 2016-12-24 )

> 但我想要预期输出：-

 Array ( [2016-12-01] => [2016-12-02] => [2016-12-05] => [2016-12-06] => [2016-12-07] => [2016-12-08] => [2016-12-09] => [2016-12-12] => [2016-12-14] => [2016-12-15] => [2016-12-16] => [2016-12-19] => [2016-12-20] => [2016-12-21] => [2016-12-22] => [2016-12-23]

你可以注意到这一点2016-12-13如“2016-12-13”所示，在上述预期输出中不存在，2016-12-24 通过假日数组作为假日传递($holidays = array( '2016-12-13', '2016-12-24', );)IE;如果我通过假期数组传递任何日期，它不应包含在结果中Array(). i:e 2016-12-13在结果数组和假日数组中可用，因此在打印最终结果时OUTPUT:- 13th date(2016-12-13)不应包含在最终输出中。任何人解决这个问题将不胜感激提前致谢。

当我必须从数组中删除重复项时，我不断返回的函数是

array array_unique ( array $array [, int $sort_flags = SORT_STRING ] )

你可以找到文档Here http://php.net/manual/en/function.array-unique.php

<?php
  $input = array("a" => "green", "red", "b" => "green", "blue", "red");
  $result = array_unique($input);
  print_r($result);
?>

输出

Array
(
    [a] => green
    [0] => red
    [1] => blue
)

我希望这能够有所帮助