如何修复 x86 Turbo 汇编语言的输出

DOSSEG
    .MODEL SMALL
    .STACK 100h
    .DATA

UserName db "Name: $"
CLRF     db 10,13,"$"
inputName db 24 dup ("$")

CurYear db "Current Year: $"
inputCurrentYear dw 8 dup ("$")

BirYear   db "Birth Year: $"
inputBirthYear dw 8 dup ("$")   

outputName db "Hello, $"

outputAge db "Your age is $"

currentYearH1 db "$"
currentYearH2 db "$"

birthYearH1 db "$"
birthYearH2 db "$"

answer1 dw "$"
answer2 dw "$"

.code

BEGIN:

;open bracket

mov ax,@data
mov ds,ax
mov es,ax

mov al,03h
mov ah, 00h
int 10h

lea dx,CLRF
mov ah,09h
int 21h

;username input

NameInput:
lea dx,UserName
mov ah, 09h
int 21h

mov inputName,21
lea dx,inputName
mov ah,0ah
int 21h

lea dx,CLRF
mov ah,09h
int 21h

;current year

CurrentYear:
lea dx,CurYear
mov ah,09h
int 21h

mov inputCurrentYear,05
lea dx,inputCurrentYear
;mov ax,dx
mov ah,0ah
int 21h

mov ax,inputCurrentYear
sub ax,3030h
xchg ah,al
aad
mov currentYearH1, al
mov ax,inputCurrentYear[4]
sub ax,3030h
xchg ah,al
aad
mov currentYearH2, al

lea dx,CLRF
mov ah,09h
int 21h

;birth year

BirthYear:
lea dx,BirYear
mov ah,09h
int 21h

mov inputBirthYear,05
lea dx,inputBirthYear
;mov bx,dx
mov ah,0ah
int 21h

mov ax, inputBirthYear[2]
sub ax,3030h
xchg ah,al
aad
mov birthYearH1,al
mov ax,inputBirthYear[4]
sub ax,3030h
xchg ah,al
aad 
mov birthYearH2,al

lea dx,CLRF
mov ah,09h
int 21h

;lea dx,inputBirthYear
;mov ah,09h
;int 21h

lea dx,CLRF
mov ah,09h
int 21h

;subtraction

;lea ax,inputCurrentYear

;lea dx,inputBirthYear

;sub ax,dx
;mov [SI],ax
;lea dx,[SI]
;mov ah,09h
int 21h
;sub ax,3030h

Output:
lea dx, outputName
mov ah,09h
int 21h

lea dx, inputName
mov ah,09h
int 21h

lea dx,CLRF
mov ah,09h
int 21h

;lea ax,inputCurrentYear

;lea dx,inputBirthYear

;sub ax,dx
;mov difference,ax

lea dx,outputAge
mov ah,09h
int 21h

lea dx,CLRF
mov ah,09h
int 21h

lea dx,CLRF
mov ah,09h
int 21h

mov al,birthYearH2
sub currentYearH2,al

mov al,birthYearH1
sub currentYearH1,al

mov al,currentYearH2
aam
add ax,3030h
xchg ah,al
mov answer2,ax

mov al,currentYearH1
aam
add ax,3030h
xchg ah,al
mov answer1,ax

lea dx, answer1
mov ah,09h
int 21h

lea dx,answer2
mov ah,09h
int 21h

lea dx,CLRF
mov ah,09h
int 21h

mov ah,4ch
int 21h    

end BEGIN

当我运行此代码时，输​​出中会出现随机符号，我想“清理”我的输出。

Int 21h/0Ah http://www.ctyme.com/intr/rb-2563.htm需要一个指向结构的指针，not指向字符串的指针。该结构的第一个字节必须由您填充字符串的最大长度。第二个字节将由函数填充输入字符串的实际长度。字符串won't根据需要以“$”结尾int 21h/09h http://www.ctyme.com/intr/rb-2562.htm，但为 0Dh。所以你需要改变这个角色。

我仅纠正了 inputName 的问题。剩下的就取决于你了。

    ...
    mov inputName,21
    lea dx,inputName
    mov ah,0ah
    int 21h

    ; change 0Dh to '$'
    xor bh,bh
    mov bl, [inputName+1]             ; length of string
    mov byte [inputName+2+bx], '$'    ; store end-of-string-character 

    ...

    lea dx, outputName
    mov ah,09h
    int 21h

    lea dx, [inputName+2]             ; pointer to string
    mov ah,09h
    int 21h

    ...