我尝试解决Leedcode问题13，问题是给定一个罗马数字，将其转换为整数。（输入保证在1到3999的范围内。）
这是我的代码，我想知道为什么它只将罗马数字中的第一个字符转换为整数？
var romanToInt = function(s) {
var result = 0;
if (s == null) {
result = 0;
}
var myMap = new Map();
myMap.set('I', 1);
myMap.set('V', 5);
myMap.set('X', 10);
myMap.set('L', 50);
myMap.set('C', 100);
myMap.set('D', 500);
myMap.set('M', 1000);
var len = s.length;
for (var i = 0; i < len; i++) {
if (myMap.get(s.charAt(i)) < myMap.get(s.charAt(i + 1))) {
result -= myMap.get(s.charAt(i))
} else {
result += myMap.get(s.charAt(i))
}
return result;
};
}
console.log(romanToInt('VI'));
console.log(romanToInt('V'));
console.log(romanToInt('VII'));
Because
return result;
一次迭代后结束循环。将其向下移动一行。如果你进行正确的格式化，你就根本不会犯这样的错误；）
const values = new Map([
['I', 1],
['V', 5],
['X', 10]
/*....*/
]);
function romanToInt(string) {
let result = 0,
current, previous = 0;
for (const char of string.split("").reverse()) {
current = values.get(char);
if (current >= previous) {
result += current;
} else {
result -= current;
}
previous = current;
}
return result;
}
console.log(romanToInt('I'));
console.log(romanToInt('II'));
console.log(romanToInt('III'));
console.log(romanToInt('IV'));
console.log(romanToInt('V'));
console.log(romanToInt('VI'));
console.log(romanToInt('VII'));
console.log(romanToInt('VIII'));
console.log(romanToInt('IX'));
console.log(romanToInt('X'));
console.log(romanToInt('XI'));
console.log(romanToInt('XII'));
console.log(romanToInt('XIII'));
console.log(romanToInt('XIV'));
console.log(romanToInt('XV'));
console.log(romanToInt('XVI'));
console.log(romanToInt('XVII'));
console.log(romanToInt('XVIII'));
console.log(romanToInt('XIX'));
console.log(romanToInt('XX'));
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