如何 Invoke-Expression 调用带有变量的函数或脚本？

我使用此脚本收到无效路径错误：

$buildZIP= 'starmatic'
echo $buildZIP
$command = ”\\XXXXXXXXXX\L$\Gopi_Prod_App\ToZipNew.ps1 $buildZIP”
Invoke-Expression -Command $command

This is ToZipNew.ps1:

Param(
    [Parameter(Position=1, Mandatory=$true)]
    [ValidateNotNullOrEmpty()]
    [string]$build
)
echo "$build"
$S = "L:\Gopi_Prod_App\$build\App_Data\*"
$D = "\Gopi_Prod_App\Starmatic_UI.zip"

echo $S
echo $D

Get-ChildItem "$S" | Compress-Archive -DestinationPath "$D" -Verbose
#Compress-Archive -Path "$S" -CompressionLevel Fastest -DestinationPath "$D"

我收到错误：

Compress-Archive : The path 'L:\Gopi_Prod_App' either does not exist or is not a
valid file system path.  
At \\XXXXXXXXXXX\L$\Gopi_Prod_App\ToZipNew.ps1:13 char:45 
+ ... t-ChildItem "$S" | Compress-Archive -DestinationPath "$D" -Verbose
+                        ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~  
    + CategoryInfo          : InvalidArgument: (L:\Gopi_Prod_App:String) [Compress-Archive], InvalidOperationException  
    + FullyQualifiedErrorId : ArchiveCmdletPathNotFound,Compress-Archive
  

Invoke-Expression is 几乎总是错误的工具 https://blogs.msdn.microsoft.com/powershell/2011/06/03/invoke-expression-considered-harmful/无论您手头有什么工作。另外，在我看来，您实际上想在remote主持人。然而，你的Invoke-Expression语句正在从远程共享读取脚本并执行它locally.

Change

$command = ”\\XXXXXXXXXX\L$\Gopi_Prod_App\ToZipNew.ps1 $buildZIP”
Invoke-Expression -Command $command

into

Invoke-Command -Computer 'XXXXXXXXXX' -ScriptBlock {
    & 'L:\Gopi_Prod_App\ToZipNew.ps1' $using:buildZIP
}

在远程主机 XXXXXXXXXX 上运行脚本。

如果您确实想在本地运行脚本，请连接共享\\XXXXXXXXXX\L$作为网络驱动器L:并从该驱动器调用脚本：

New-PSDrive -Name 'L' -PSProvider FileSystem -Root '\\XXXXXXXXXX\L$' -Persist
& 'L:\Gopi_Prod_App\ToZipNew.ps1' $buildZIP
Remove-PSDrive -Name 'L'