回复主题 google-api-ruby-client

下面是我使用 google-api-ruby-client 创建消息的代码（几乎）的样子：

  service ||= Google::Apis::GmailV1::GmailService.new

  message = RMail::Message.new
  message.header['To'] = params[:gmail][:to]
  message.header['From'] = current_user_google_user_id
  message.header['Subject'] = params[:gmail][:subject]
  message.header['Subject'] = params[:gmail][:subject]
  message.body = params[:gmail][:body]

  service.send_user_message(
    current_user_google_user_id,
    upload_source: StringIO.new(message.to_s),
    content_type: 'message/rfc822',
    thread_id: params[:gmail][:thread_id]
  )

它显然失败了，因为我有thread_id。如果我删除该行，一切都会正常工作，但我无法将事情限制在线程范围内。我应该如何将线程 ID 传递给 GmailService？

查看 GitHub 上的源代码send_user_message https://github.com/google/google-api-ruby-client/blob/e3b8c800d649da00748d4605d847b342480ecc73/generated/google/apis/gmail_v1/service.rb#L1150表明它不需要thread_id作为参数。但是，那Message class https://github.com/google/google-api-ruby-client/blob/e3b8c800d649da00748d4605d847b342480ecc73/generated/google/apis/gmail_v1/classes.rb#L838确实有它作为一个属性。

所以也许尝试这个应该有效：

  service ||= Google::Apis::GmailV1::GmailService.new

  message = RMail::Message.new
  message.header['To'] = params[:gmail][:to]
  message.header['From'] = current_user_google_user_id
  message.header['Subject'] = params[:gmail][:subject]
  message.header['Subject'] = params[:gmail][:subject]
  message.body = params[:gmail][:body]
  message.thread_id = params[:gmail][:thread_id]

  service.send_user_message(
    current_user_google_user_id,
    upload_source: StringIO.new(message.to_s),
    content_type: 'message/rfc822'
  )