使用 stripplot 在 seaborn 中用中线绘制点

我在seaborn中有以下情节：

df = pandas.DataFrame({"sample": ["X", "X", "X", "Y", "Y", "Y"],
                       "value": [0.2, 0.3, 0.4, 0.7, 0.75, 0.8],
                       "rep": ["a", "b", "c", "a", "b", "c"]})
plt.figure()
ax = sns.stripplot(x="sample", y="value", edgecolor="none",
                   hue="sample", palette="Set1", data=df)

# how to plot median line?
plt.show()

它以灰度颜色绘制点而不是使用Set1并且只显示X传说中而不是Y:

我还想在中线处添加一条水平线X and Y。如何才能做到这一点？factorplot似乎没有水平线选项。

我们可以在生成带状图后通过循环轴刻度和刻度标签来限制每条中线到其各自列的宽度。这也使得代码能够独立于要绘制的样本（列）的数量进行操作。

    import pandas as pd
    import seaborn as sns
    import matplotlib.pyplot as plt

    df = pd.DataFrame({"sample": ["X", "X", "X", "Y", "Y", "Y"],
                       "value": [0.2, 0.3, 0.4, 0.7, 0.75, 0.8],
                       "rep": ["a", "b", "c", "a", "b", "c"]})

    ax = sns.stripplot(x="sample", y="value", data=df, palette="Set1", s=8)

    # distance across the "X" or "Y" stipplot column to span, in this case 40%
    median_width = 0.4

    for tick, text in zip(ax.get_xticks(), ax.get_xticklabels()):
        sample_name = text.get_text()  # "X" or "Y"

        # calculate the median value for all replicates of either X or Y
        median_val = df[df['sample']==sample_name].value.median()

        # plot horizontal lines across the column, centered on the tick
        ax.plot([tick-median_width/2, tick+median_width/2], [median_val, median_val],
                lw=4, color='k')

    plt.show()

seaborn stripplot with median lines drawn: