使用 C# 比较嵌套对象属性

我有一个方法可以比较两个对象并返回所有不同属性名称的列表。

public static IList<string> GetDifferingProperties(object source, object target)
{
    var sourceType = source.GetType();
    var sourceProperties = sourceType.GetProperties();
    var targetType = target.GetType();
    var targetProperties = targetType.GetProperties();

    var properties = (from s in sourceProperties
                      from t in targetProperties
                      where s.Name == t.Name &&
                            s.PropertyType == t.PropertyType &&
                            s.GetValue(source,null) != t.GetValue(target,null)
                      select s.Name).ToList();
    return properties;
}

例如，如果我有两个类，如下所示：

public class Address
    {
        public string AddressLine1 { get; set; }
        public string AddressLine2 { get; set; }
        public string City { get; set; }
        public string State { get; set; }
        public string Zip { get; set; }
    }

       public class Employee
        {
            public string FirstName { get; set; }
            public string MiddleName { get; set; }
            public string LastName { get; set; }
            public Address EmployeeAddress { get; set; }
        }

我试图比较以下两个员工实例：

var emp1Address = new Address();
        emp1Address.AddressLine1 = "Microsoft Corporation";
        emp1Address.AddressLine2 = "One Microsoft Way";
        emp1Address.City = "Redmond";
        emp1Address.State = "WA";
        emp1Address.Zip = "98052-6399";

        var emp1 = new Employee();
        emp1.FirstName = "Bill";
        emp1.LastName = "Gates";
        emp1.EmployeeAddress = emp1Address;


        var emp2Address = new Address();
        emp2Address.AddressLine1 = "Gates Foundation";
        emp2Address.AddressLine2 = "One Microsoft Way";
        emp2Address.City = "Redmond";
        emp2Address.State = "WA";
        emp2Address.Zip = "98052-6399";

        var emp2 = new Employee();
        emp2.FirstName = "Melinda";
        emp2.LastName = "Gates";
        emp2.EmployeeAddress = emp2Address;

因此，当我将这两个员工对象传递给 GetDifferingProperties 方法时，当前它会返回 FirstName 和 EmployeeAddress，但它不会告诉我 EmployeeAddress 中的哪个确切属性（在本例中为 Address1）已更改。我如何调整此方法以获得类似 EmployeeAddress.Address1 的内容？

这是因为你正在使用!=对于对象，它测试对象的身份而不是其值。关键是使用递归来生成属性的属性列表。这将按照你想要的深度进行...

public static IList<string> GetDifferingProperties(object source, object target)
{
  var sourceType = source.GetType();
  var sourceProperties = sourceType.GetProperties();
  var targetType = target.GetType();
  var targetProperties = targetType.GetProperties();

  var result = new List<string>();

  foreach (var property in
      (from s in sourceProperties
       from t in targetProperties
       where s.Name == t.Name &&
       s.PropertyType == t.PropertyType &&
       !Equals(s.GetValue(source, null), t.GetValue(target, null))
       select new { Source = s, Target = t }))
  {
    // it's up to you to decide how primitive is primitive enough
    if (IsPrimitive(property.Source.PropertyType))
    {
      result.Add(property.Source.Name);
    }
    else
    {
      foreach (var subProperty in GetDifferingProperties(
          property.Source.GetValue(source, null),
          property.Target.GetValue(target, null)))
      {
        result.Add(property.Source.Name + "." + subProperty);
      }
    }
  }

  return result;
}

private static bool IsPrimitive(Type type)
{
  return type == typeof(string) || type == typeof(int);
}