我无法覆盖 jms 序列化程序包中的默认处理程序。
我想改变方式Symfony\Component\Validator\ConstraintViolationList
已序列化,因此我编写了自己的自定义处理程序。并按照文档(以及各种 stackoverflow 答案)中的描述正确标记它。
但是,我的处理程序不断被 JMS Serializer 捆绑包附带的 ConstraintViolationList 的默认处理程序覆盖。
我已正确标记我的处理程序服务。事实上,当我注释掉时,我的处理程序服务被检测到并正确使用ms_serializer.constraint_violation_handler
服务定义来自vendor/jms/serializer-bundle/JMS/SerializerBundle/Resources/config/services.xml
如何阻止默认处理程序覆盖我的自定义处理程序?
我什至尝试过覆盖jms_serializer.constraint_violation_handler.class
来自我自己的包的参数但仍然没有运气。
这是我的处理程序类:
<?php
namespace Coanda\Bridge\JMSSerializer\Handler;
use JMS\Serializer\Context;
use JMS\Serializer\GraphNavigator;
use JMS\Serializer\Handler\SubscribingHandlerInterface;
use JMS\Serializer\JsonSerializationVisitor;
use Symfony\Component\Validator\ConstraintViolation;
use Symfony\Component\Validator\ConstraintViolationList;
class ConstraintViolationHandler implements SubscribingHandlerInterface
{
public static function getSubscribingMethods()
{
$methods = [];
$methods[] = [
'direction' => GraphNavigator::DIRECTION_SERIALIZATION,
'type' => ConstraintViolationList::class,
'format' => 'json',
'method' => 'serializeListToJson'
];
return $methods;
}
public function serializeListToJson(
JsonSerializationVisitor $visitor,
ConstraintViolationList $list,
array $type,
Context $context
) {
$violations = [];
foreach ($list as $item) {
$violations[$item->getPropertyPath()][] = $item->getMessage();
}
if (null === $visitor->getRoot()) {
$visitor->setRoot($violations);
}
return $violations;
}
}
我已将其注册在我的services.xml
<service id="coanda.serializer.constraint_violation_handler"
class="Coanda\Bridge\JMSSerializer\Handler\ConstraintViolationHandler">
<tag name="jms_serializer.subscribing_handler"
type="Symfony\Component\Validator\ConstraintViolationList"
direction="serialization" format="json" method="serializeListToJson" />
</service>