您将获得数组中最大值的第三个容器(我假设您有一个拼写错误,并且 max_x 应该是“max(my_array[:,0])”而不是“max(my_array[:,1”) ])”)。您可以通过向最后一个 bin 添加 1(或任何正数)来避免这种情况。
另外,如果我理解正确的话,您希望将一个变量与另一个变量分开,所以我下面的示例表明了这一点。如果您使用 recarrays(速度慢得多),matplotlib.mlab 中还有几个函数(例如 mlab.rec_groupby 等)可以执行此类操作。
不管怎样,最后,你可能会得到这样的结果(用 y 中的值对 x 进行装箱,假设 x 和 y 的长度相同)
def bin_by(x, y, nbins=30):
"""
Bin x by y.
Returns the binned "x" values and the left edges of the bins
"""
bins = np.linspace(y.min(), y.max(), nbins+1)
# To avoid extra bin for the max value
bins[-1] += 1
indicies = np.digitize(y, bins)
output = []
for i in xrange(1, len(bins)):
output.append(x[indicies==i])
# Just return the left edges of the bins
bins = bins[:-1]
return output, bins
举个简单的例子:
In [3]: x = np.random.random((100, 2))
In [4]: binned_values, bins = bin_by(x[:,0], x[:,1], 2)
In [5]: binned_values
Out[5]:
[array([ 0.59649575, 0.07082605, 0.7191498 , 0.4026375 , 0.06611863,
0.01473529, 0.45487203, 0.39942696, 0.02342408, 0.04669615,
0.58294003, 0.59510434, 0.76255006, 0.76685052, 0.26108928,
0.7640156 , 0.01771553, 0.38212975, 0.74417014, 0.38217517,
0.73909022, 0.21068663, 0.9103707 , 0.83556636, 0.34277006,
0.38007865, 0.18697416, 0.64370535, 0.68292336, 0.26142583,
0.50457354, 0.63071319, 0.87525221, 0.86509534, 0.96382375,
0.57556343, 0.55860405, 0.36392931, 0.93638048, 0.66889756,
0.46140831, 0.01675165, 0.15401495, 0.10813141, 0.03876953,
0.65967335, 0.86803192, 0.94835281, 0.44950182]),
array([ 0.9249993 , 0.02682873, 0.89439141, 0.26415792, 0.42771144,
0.12292614, 0.44790357, 0.64692616, 0.14871052, 0.55611472,
0.72340179, 0.55335053, 0.07967047, 0.95725514, 0.49737279,
0.99213794, 0.7604765 , 0.56719713, 0.77828727, 0.77046566,
0.15060196, 0.39199123, 0.78904624, 0.59974575, 0.6965413 ,
0.52664095, 0.28629324, 0.21838664, 0.47305751, 0.3544522 ,
0.57704906, 0.1023201 , 0.76861237, 0.88862359, 0.29310836,
0.22079126, 0.84966201, 0.9376939 , 0.95449215, 0.10856864,
0.86655289, 0.57835533, 0.32831162, 0.1673871 , 0.55742108,
0.02436965, 0.45261232, 0.31552715, 0.56666458, 0.24757898,
0.8674747 ])]
希望有点帮助!