假设我有一些这样的文字，
text<-c("[McCain]: We need tax policies that respect the wage earners and job creators. [Obama]: It's harder to save. It's harder to retire. [McCain]: The biggest problem with American healthcare system is that it costs too much. [Obama]: We will have a healthcare system, not a disease-care system. We have the chance to solve problems that we've been talking about... [Text on screen]: Senators McCain and Obama are talking about your healthcare and financial security. We need more than talk. [Obama]: ...year after year after year after year. [Announcer]: Call and make sure their talk turns into real solutions. AARP is responsible for the content of this advertising.")
我想删除（编辑：摆脱） [ 和 ] （以及括号本身）之间的所有文本。最好的方法是什么？这是我使用正则表达式和 stingr 包的无力尝试：
str_extract(text, "\\[[a-z]*\\]")
谢谢你的帮助！
有了这个：
gsub("\\[[^\\]]*\\]", "", subject, perl=TRUE);
正则表达式的含义：
\[ # '['
[^\]]* # any character except: '\]' (0 or more
# times (matching the most amount possible))
\] # ']'
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