我在 Windows Phone 8.1 应用程序中使用 RestSharp。当服务器返回代码不同于 200 的响应时,RestClient 会抛出异常。Wiki https://github.com/restsharp/RestSharp/wiki/Getting-Started说我应该得到正确状态代码的响应。我想获取响应内容,因为服务器返回错误消息。
private async Task<T> ExecuteAsync<T>(IRestRequest request)
{
if (!_networkAvailableService.IsNetworkAvailable)
{
throw new NoInternetException();
}
request.AddHeader("Accept", "application/json");
IRestResponse<T> response;
try
{
response = await _client.Execute<T>(request); //here I get exception
}
catch (Exception ex)
{
throw new ApiException();
}
HandleApiException(response);
return response.Data;
}
private void HandleApiException(IRestResponse response)
{
if (response.StatusCode == HttpStatusCode.OK)
{
return;
}
//never reach here :(
ApiException apiException;
try
{
var apiError = _deserializer.Deserialize<ApiErrorResponse>(response);
apiException = new ApiException(apiError);
}
catch (Exception)
{
throw new ApiException();
}
throw apiException;
}
服务器响应示例:
HTTP/1.1 400 Bad Request
Cache-Control: no-cache
Pragma: no-cache
Content-Length: 86
Content-Type: application/json;charset=UTF-8
Expires: -1
Server: Microsoft-IIS/8.0
Access-Control-Allow-Origin: *
X-Powered-By: ASP.NET
Date: Mon, 28 Sep 2015 12:30:10 GMT
Connection: close
{"error":"invalid_token","error_description":"The user name or password is incorrect"}
如果您在 Windows Phone 8.1 下工作,则您正在使用 RestSharp Portable (https://github.com/FubarDevelopment/restsharp.portable https://github.com/FubarDevelopment/restsharp.portable) (大概)。
用这个:
var client = new RestClient();
client.IgnoreResponseStatusCode = true;
这样,您就不会遇到 404 等异常。
我希望这会有所帮助:)
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