if
/dt/@id
returns comment_34232 or comment_12我怎样才能让它返回34232 or 12（换句话说，替换'comment_' with ''
and if
/span/style
returns width: 80%;我怎样才能更换width:在那之后%;检索80
Regards
I. Part
if
/dt/@id returns `comment_34232` or `comment_12` how can I make it return
34232 or 12（换句话说
更换'comment_' with ''
Use:
substring-after(/dt/@id, '_')
II. Part
and if
/span/style returns `width: 80%;` how can I replace `width: ` and after
that %;检索80
Use:
substring-before(substring-after(/span/style, ' '), '%')
Do note：使用标准XPath函数substring-before() http://www.w3.org/TR/1999/REC-xpath-19991116/#function-substring-before and substring-after() http://www.w3.org/TR/1999/REC-xpath-19991116/#function-substring-after .
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