Paramiko：收集输出的 ssh.exec_command 表示打开通道作为响应

我有带有 paramiko 和 ssh 的 python 脚本，如下所示

import paramiko

# setup ssh connection this works. no problem.
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
conn = ssh.connect(MACHINEIP, username=ROOTUSER, password=ROOTUSER_PASSWORD, port=22)

# This first ssh exec works perfect. 
(sshin1, sshout1, ssherr1) = ssh.exec_command(cmd1)

# When I print the output of 2nd and 3rd ssh exec, I get output saying of channel open
(sshin2, sshout2, ssherr2) = ssh.exec_command(cmd2)
print sshout2
(sshin3, sshout3, ssherr3) = ssh.exec_command(cmd3)
print sshout3

当多次使用 exec_command 收集输出时，输出中的通道打开消息：

<paramiko.ChannelFile from <paramiko.Channel 2 (open) window=2097152 
   -> <paramiko.Transport at 0x1d42bd0L (cipher aes128-ctr, 128 bits) 
(active; 1 open channel(s))>>>

<paramiko.ChannelFile from <paramiko.Channel 6 (open) window=2097152 
   -> <paramiko.Transport at 0x1d42bd0L (cipher aes128-ctr, 128 bits) 
(active; 2 open channel(s))>>>

我怎样才能关闭这个开放的通道？或者对此有什么解决方案吗？我正在使用Python 2.7。

应该用作sshout.read()相反我用了sshout仅在打印时。