我有一个 256 个字符长的字符串,其中包含一个十六进制值:
EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9 E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679
我想将其转换为带有数字的字符串,如下所示:
1027214340374524092449470645761685057074800357622629340269412121814737852259288791781240281401345826979864279828010888845 539653717868569674767960724331689898603798857627272145505281989410385829377881458809038822939990221818476657354126291580694 72562567144696160522107094738216218810820997773451212693036210879
这么大的数字怎么办呢?
提前致谢。
Use BigInteger http://msdn.microsoft.com/en-us/library/system.numerics.biginteger.aspx。具体来说,您可以使用BigInteger.Parse http://msdn.microsoft.com/en-us/library/dd268285.aspx将十六进制表示解析为实例BigInteger
(use NumberStyles.HexNumber http://msdn.microsoft.com/en-us/library/system.globalization.numberstyles.aspx), 进而BigInteger.ToString http://msdn.microsoft.com/en-us/library/dd268341.aspx获得十进制表示形式。
var number = BigInteger.Parse(
"EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679",
NumberStyles.HexNumber
);
var s = number.ToString();
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