我无法访问另一个类中一个类的成员函数,尽管我可以在 main() 中很好地访问它。我一直在尝试扭转局面,但无法理解我做错了什么。任何帮助,将不胜感激。
这是生成错误的行:
cout << "\n\nRetrieve key from inside Envelope class: " << e.getData() << "\n\n";
这是代码:
class Record{
private:
string key;
public:
Record(){ key = ""; }
Record(string input){ key = input; }
string getData(){ return key; }
Record operator= (string input) { key = input; }
};
template<class recClass>
class Envelope{
private:
recClass * data;
int size;
public:
Envelope(int inputSize){
data = new recClass[inputSize];
size = 0;
}
~Envelope(){ delete[] data; }
void insert(const recClass& e){
data[size] = e;
cout << "\n\nRetrieve key from inside Envelope class: " << e.getData() << "\n\n";
++size;
}
string getRecordData(int index){ return data[index].getData(); }
};
int main(){
Record newRecord("test");
cout << "\n\nRetrieve key directly from Record class: " << newRecord.getData() << "\n\n";
Envelope<Record> * newEnvelope = new Envelope<Record>(5);
newEnvelope->insert(newRecord);
cout << "\n\nRetrieve key through Envelope class: " << newEnvelope->getRecordData(0) << "\n\n";
delete newEnvelope;
cout << "\n\n";
return 0;
}
你正在路过e
作为恒定的参考void insert(const recClass& e){
然后你调用一个方法(getData()
) 未声明为常量。
您可以通过重写来修复它getData()
像这样:
string getData() const{ return key; }
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)