在汇编程序中将十进制转换为二进制

我的第一个汇编程序需要帮助。 我必须将用户输入的值从十进制转换为二进制。 我不知道如何将值显示为小数，以及下一步应该做什么。 谁能一步一步指导我下一步做什么。

    .model small
    .stack 100h`

    .data
            txt1 db "Enter binary value:" ,10,13, "$"
            txt2 db "BIN: " ,10,13, "$"


    .code

        main proc
        mov ax, @data
        mov ds, ax
        ;clear screen
        mov ah,0fh
        int 10h
        mov ah,0
        int 10h
        ;show first text
        mov ah, 9
        mov dx, offset txt1
        int 21h
        call Number


        main endp


        Number proc
        mov cx,5
        xor bx,bx

        read:
        mov ah,0
        int 16h
        cmp al,'0'
        jb read
        cmp al, '9'
        ja read
        mov ah,0eh
        int 10h
        loop read
        Number endp

        mov ax, 4c00h
        int 21h

        end main

我想这对你来说没问题。

; Read an integer from the screen and display the int in binary format
; and continue until number is negative.
again:            ; For loop
    call read_int ; take the integer from screen
    cmp eax,0     ; look if number is not negative
        JL end:       ; if less than zero program ends.
    mov ecx,32    ; for loop we set ecx to 32 ; ATTENTION we not specified type. So compiler will get error.

    mov ebx,eax   ; we will lost our number in eax, so I take it to ebx
START:
    xor eax,eax   ; eax = 0
    SHL ebx,1     ; shift the top bit out of EBX into CF
    ADC eax,0     ; EAX  = EAX + CF + 0 ADD CARRY FLAG, so eax is zero we add zero. The new eax will exact value of Carry Flag which is out bit.
    call print_int ; Then we print the CF which we took the eax.
LOOP start:   ; Loop looks ecx if not 0 it goes start.  
call print_nl ; For next number we print a new line
JMP again:    ; For take new number

    END:      ; End of the program.

setc al也可以代替adc eax,0，并且在某些 CPU 上效率更高。