如何在 Linux 中获取 Apache 的“每秒请求数”？

在 Windows for ASP 中，您可以获得 perfmon，但是...

如何获得“每秒请求数”Linux 下的 Apache？

这是我编写的一个简短的 bash 脚本，用于对请求率进行采样（基于迪克塞的建议 https://stackoverflow.com/questions/345546/how-to-get-requests-per-second-for-apache-in-linux/345588#345588使用的wc -l在日志文件中）。

#!/bin/sh

##############################################################################
# This script will monitor the number of lines in a log file to determine the
# number of requests per second.
#
# Example usage:
# reqs-per-sec -f 15 -i /var/www/http/access.log
#
# Author: Adam Franco
# Date: 2009-12-11
# License: http://www.gnu.org/copyleft/gpl.html GNU General Public License (GPL)
##############################################################################

usage="Usage: `basename $0` -f <frequency in seconds, min 1, default 60> -l <log file>"

# Set up options
while getopts ":l:f:" options; do
 case $options in
 l ) logFile=$OPTARG;;
 f ) frequency=$OPTARG;;
 \? ) echo -e $usage
  exit 1;;
 * ) echo -e $usage
  exit 1;;

 esac
done

# Test for logFile
if [  ! -n "$logFile" ]
then
 echo -e $usage
 exit 1
fi

# Test for frequency
if [  ! -n "$frequency" ]
then
 frequency=60
fi

# Test that frequency is an integer
if [  $frequency -eq $frequency 2> /dev/null ]
then
 :
else
 echo -e $usage
 exit 3
fi

# Test that frequency is an integer
if [  $frequency -lt 1 ]
then
 echo -e $usage
 exit 3
fi

if [ ! -e "$logFile" ]
then
 echo "$logFile does not exist."
 echo 
 echo -e $usage
 exit 2
fi

lastCount=`wc -l $logFile | sed 's/\([0-9]*\).*/\1/'`
while true
do
 newCount=`wc -l $logFile | sed 's/\([0-9]*\).*/\1/'`
 diff=$(( newCount - lastCount ))
 rate=$(echo "$diff / $frequency" |bc -l)
 echo $rate
 lastCount=$newCount
 sleep $frequency
done