我在 VS2010 中使用 OpenCV 2.4.6。
我认为我的网络摄像头无法捕获该帧。当我执行代码时,它构建成功,但我没有得到输出。我想,当我检查时if(!bSuccess)
它已执行并且无法从网络摄像头捕获帧。
我该如何解决这个问题?我的代码如下:
#include "opencv2/highgui/highgui.hpp"
#include
using namespace cv;
using namespace std;
int main(int argc, char* argv[])
{
VideoCapture cap(0); // open the video camera no. 0
if (!cap.isOpened()) // if not success, exit program
{
cout << "Cannot open the video file" << endl;
return -1;
}
double dWidth = cap.get(CV_CAP_PROP_FRAME_WIDTH); //get the width of frames of the video
double dHeight = cap.get(CV_CAP_PROP_FRAME_HEIGHT); //get the height of frames of the video
cout << "Frame size : " << dWidth << " x " << dHeight << endl;
namedWindow("MyVideo",CV_WINDOW_AUTOSIZE); //create a window called "MyVideo"
while (1)
{
Mat frame;
bool bSuccess = cap.read(frame); // read a new frame from video
if (!bSuccess) //if not success, break loop
{
cout << "Cannot read a frame from video file" << endl;
break;
}
imshow("MyVideo", frame); //show the frame in "MyVideo" window
if (waitKey(30) == 27)
{
cout << "esc key is pressed by user" << endl;
break;
}
}
return 0;
}
添加这一行cap.retrieve(frame);
在与之前bool bSuccess = cap.read(frame);
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