控制台错误“非法的base64字符20”[关闭]

我使用以下代码进行加密和解密，而解密时我在运行时收到错误。错误消息是“非法的 base64 字符 20”

加密代码：

String secretValue = "sazhwsxplokmeroo";
keyValue = secretValue.getBytes();
Key generatedKey = generateKey();
Cipher c = Cipher.getInstance(ALGO);
c.init(Cipher.ENCRYPT_MODE, generatedKey);
byte[] encValue = c.doFinal(userEmail.getBytes());
String encryptedValue = Base64.getEncoder().encodeToString(encValue);

密钥：

 private Key generateKey() {
     Key secretKey = new SecretKeySpec(keyValue, ALGO);
     return secretKey;
}

解密代码：

String secretValue = "sazhwsxplokmeroo";
keyValue = secretValue.getBytes();
Key generatedKey = generateKey();
Cipher c = Cipher.getInstance(ALGO);
c.init(Cipher.DECRYPT_MODE, generatedKey);
byte[] decodedValue = Base64.getDecoder().decode(encryptEmail.getBytes()); //error throws from this line as illegal base64 character 20
byte[] decValue = c.doFinal(decodedValue);
String decryptedValue = decValue.toString();

如何解密加密值而不出错

加密值 = 3aW0qv4pN+y3Tj8raXDHtos95ChpLu2JzEnfW+KfgEE=

该值在弹簧控制器中显示为 = 3aW0qv4pN y3Tj8raXDHtos95ChpLu2JzEnfW KfgEE=

它显示两个空格“+”转换为“（空格）”

现在我已将密钥更改为“sa278asabmnbmnbm”

我得到的加密值为 40SRNEe9PgaxEeprPyqlyeP08hBHq00Ow9WWBgP6ZTM=

解密时我得到 [B@75141845 作为解密值

预期的 ：[电子邮件受保护] /cdn-cgi/l/email-protection