Express js：将多个路由文件合并为单个文件

在我的express.js应用程序中，我按以下方式组织我的路线

paths/comment.js(处理所有评论路由)

var express = require('express');
var router = express.Router();
var comment = require('../controller/comment');
router.route('/new').get(comment.create);
module.exports = router;

routes/post.js(处理所有post路由)

var express = require('express');
var router = express.Router();
var post = require('../controller/post');
router.route('/new').get(post.create);
module.exports = router;

我包括在app.js像这样文件

//need to include these declarations into another file and include that file here
  //eg: require('config/main-routes');

    /*
     routes like comment/new
    */
    var comment  = require('./routes/comment');
    app.use('/comment',comment);
    /*
     routes like post/new
    */
    var post  = require('./routes/post');
    app.use('/post',post)

这工作正常，但是我想将其包含到另一个文件中config/route-main.js并将其链接到app.js file

我怎样才能做到这一点？？

in app.js include

var routes  = require('./config/route-main');
app.use('/',routes);

和在route-config.js中

var express = require('express');
var router = express.Router();
var comment  = require('./routes/comment');
var post  = require('./routes/post');

router.use('/comment',comment);
router.use('/post',post)


module.exports = router

检查此链接：

https://katieleonard.ca/blog/2016/2016-04-12-nested-routes-with-expressjs/ https://katieleonard.ca/blog/2016/2016-04-12-nested-routes-with-expressjs/