我正在基于react redux构建一个文件管理器webui(我的目的是通过这个项目掌握react和redux)
如您所知,文件管理器需要一个树浏览器。我想构建一个可以包含它自己并且每个都有自己状态的组件。像下面这样:
TreeNode
可以包含子项TreeNode
也是。每个TreeNode
保持其状态{path, children_nodes, right .....}
, children_nodes
是从服务器获取的,path
是由家长传递的。这就是我的想象。
结构如下:
App:
TreeNode
--TreeNode
----TreeNode
----TreeNode
TreeNode
TreeNode
--TreeNode
TreeNode
--TreeNode
----TreeNode
----TreeNode
但麻烦来了,因为 reduxconnect
存储到树根,根下的所有节点接收相同的状态...
For example, I have a OPEN_NODE
action, which is design to trigger getFileList fucntion
base this node's path and set this node's state.open
to true
.(note: getFileList fucntion
not implement yet, just give fake data for now)
The screen shot:
单击每个元素,但是states are equal
.
My code:
容器/App.js
import React, { Component, PropTypes } from 'react';
import { bindActionCreators } from 'redux';
import { connect } from 'react-redux';
import Footer from '../components/Footer';
import TreeNode from '../containers/TreeNode';
import Home from '../containers/Home';
import * as NodeActions from '../actions/NodeActions'
export default class App extends Component {
componentWillMount() {
// this will update the nodes on state
this.props.actions.getNodes();
}
render() {
const { nodes } = this.props
console.log(nodes)
return (
<div className="main-app-container">
<Home />
<div className="main-app-nav">Simple Redux Boilerplate</div>
<div>
{nodes.map(node =>
<TreeNode key={node.name} info={node} actions={this.props.actions}/>
)}
</div>
{/*<Footer />*/}
</div>
);
}
}
function mapStateToProps(state) {
return {
nodes: state.opener.nodes,
open: state.opener.open
};
}
function mapDispatchToProps(dispatch) {
return {
actions: bindActionCreators(NodeActions, dispatch)
};
}
export default connect(
mapStateToProps,
mapDispatchToProps
)(App);
容器/TreeNode.js
import React, { Component, PropTypes } from 'react'
import { bindActionCreators } from 'redux'
import { connect } from 'react-redux'
import classNames from 'classnames/bind'
import * as NodeActions from '../actions/NodeActions'
export default class TreeNode extends Component {
constructor(props, context) {
super(props, context)
this.props = {
open: false,
nodes: [],
info:{}
}
}
handleClick() {
let {open} = this.props
if (open) {
this.props.actions.closeNode()
} else {
this.props.actions.openNode()
}
}
render() {
const { actions, nodes, info } = this.props
return (
<div className={classNames('tree-node', { 'open':this.props.open})} onClick={ () => {this.handleClick()} }>
<a>{info.name}</a>
{nodes &&
<div>{nodes.map(node => <TreeNode info={node} />)}</div>
}
{!nodes &&
<div>no children</div>
}
</div>
);
}
}
TreeNode.propTypes = {
open:PropTypes.bool,
info:PropTypes.object.isRequired,
nodes:PropTypes.array,
actions: PropTypes.object.isRequired
}
动作/NodeActions.js
import { OPEN_NODE, CLOSE_NODE, GET_NODES } from '../constants/NodeActionTypes';
export function openNode() {
return {
type: OPEN_NODE
};
}
export function closeNode() {
return {
type: CLOSE_NODE
};
}
export function getNodes() {
return {
type: GET_NODES
};
}
减速器/TreeNodeReducer.js
import { OPEN_NODE, CLOSE_NODE, GET_NODES } from '../constants/NodeActionTypes';
const initialState = {
open: false,
nodes: [],
info: {}
}
const testNodes = [
{name:'t1',type:'t1'},
{name:'t2',type:'t2'},
{name:'t3',type:'t3'},
]
function getFileList() {
return {
nodes: testNodes
}
}
export default function opener(state = initialState, action) {
switch (action.type) {
case OPEN_NODE:
var {nodes} = getFileList()
return {
...state,
open:true,
nodes:nodes
};
case CLOSE_NODE:
return {
...state,
open:false
};
case GET_NODES:
var {nodes} = getFileList()
return {
...state,
nodes:nodes
};
default:
return state;
}
}
完整代码见我的githubhttps://github.com/eromoe/simple-redux-boilerplate https://github.com/eromoe/simple-redux-boilerplate
我没有看到涵盖此类组件的示例,并且谷歌结果没有任何帮助。
有什么想法可以克服这个问题吗?
update:
我看到这个如何在reactjs中管理树组件中的状态 https://stackoverflow.com/questions/20503559/how-to-manage-state-in-a-tree-component-in-reactjs
但解决方案是将整个树传递给状态,不能在文件管理器中使用。