表达方式
age('2012-11-30 00:00:00'::timestamp, '2012-10-31 00:00:00'::timestamp)
gives 30 days
。我们在期待1 month
因为这两个值都指向该月的最后几天。如果我们在值中添加 1 天,我们将得到下个月的第一天,
age('2012-12-01 00:00:00'::timestamp, '2012-11-01 00:00:00'::timestamp)
预计会给我们 1 个月的时间。因此,让我们检查是否有该月的最后两天,在这种情况下返回接下来几天的年龄间隔。在其他情况下,我们将返回原始值的年龄区间:
create or replace function age_m (t1 timestamp, t2 timestamp)
returns interval language plpgsql immutable
as $$
declare
_t1 timestamp = t1+ interval '1 day';
_t2 timestamp = t2+ interval '1 day';
begin
if extract(day from _t1) = 1 and extract(day from _t2) = 1 then
return age(_t1, _t2);
else
return age(t1, t2);
end if;
end $$;
一些例子:
with my_table(date1, date2) as (
values
('2012-11-30 00:00:00'::timestamp, '2012-10-31 00:00:00'::timestamp),
('2012-12-31 00:00:00'::timestamp, '2012-10-31 00:00:00'::timestamp),
('2013-01-31 00:00:00'::timestamp, '2012-10-31 00:00:00'::timestamp),
('2013-02-28 00:00:00'::timestamp, '2012-10-31 00:00:00'::timestamp)
)
select *, age(date1, date2), age_m(date1, date2)
from my_table
date1 | date2 | age | age_m
---------------------+---------------------+----------------+--------
2012-11-30 00:00:00 | 2012-10-31 00:00:00 | 30 days | 1 mon
2012-12-31 00:00:00 | 2012-10-31 00:00:00 | 2 mons | 2 mons
2013-01-31 00:00:00 | 2012-10-31 00:00:00 | 3 mons | 3 mons
2013-02-28 00:00:00 | 2012-10-31 00:00:00 | 3 mons 28 days | 4 mons
(4 rows)