pygame中盒子的连续移动

我编写了以下代码来创建一个简单的游戏，当您单击键盘上的箭头时，一个框会在游戏中移动一个单位。

我试图做到这一点，以便如果我按下任何箭头按钮，盒子将继续朝该方向移动，直到按下另一个箭头。因此，如果我按一次向右箭头而不是快速移动 +50 像素，它将在屏幕上连续移动，直到单击不同的箭头，然后它就会朝那个方向移动

import pygame #importing the pygame library

# some initializations
pygame.init()  # this line initializes pygame
window = pygame.display.set_mode( (800,600) ) # Create a window with   width=800 and height=600
pygame.display.set_caption( 'Rectangle move' ) # Change the window's name we create to "Rectangle move"
clock = pygame.time.Clock() # Clocks are used to track and control the frame-rate of a game (how fast and how slow the pace of the game)
                        # This line creates and initializes a clock.

# color definitions, using RBG color model.
black = (0,0,0)
white = (255,255,255)

# initial center position for the square (bob)
x,y = 0,0
lastKey=0
game_loop=True
while game_loop:
    for event in pygame.event.get():   # loop through all events
        if event.type == pygame.QUIT:
            game_loop = False # change the game_loop boolean to False to quit.
        if event.type == pygame.KEYDOWN: 
            lastKey = event.key
    #check last entered key
    #lastKey equals "LEFT", "RIGHT", "UP", "DOWN" --> do the required stuff!
    #set x coordinate minus 50 if left was pressed
    if lastKey == pygame.K_LEFT:
         x -= 50
    if lastKey == pygame.K_RIGHT:
         x += 50
    if lastKey == pygame.K_UP:
         y += 50
    if lastKey == pygame.K_DOWN:
         y -= 50
    if event.key == pygame.K_LEFT:
          x -= 50
    if event.key == pygame.K_RIGHT:
          x += 50
    if event.key == pygame.K_UP:
          y += 50
    if event.key == pygame.K_DOWN:
          y -= 50
 # draw and update screen
 window.fill( black ) # fill the screen with black overwriting even bob.
 pygame.draw.rect( window, white, (x, y, 50, 50) ) # draw bob on the screen with new coordinates after its movement.
                                                      # the parameters are as follows: window: is the window object you want to draw on. white: the object color used to fill the rectangle
                                                      # (x,y,50,50) x is the x position of the left side of the rectangle. y is the y position of the upper side of the rectangle. 
                                                      # In other words (x,y) is the coordinate of the top left point of the rectangle.
                                                      # 50 is the width, and 50 is the height
 pygame.display.update() #updates the screen with the new drawing of the rectangle.

#fps stuff:
 clock.tick(10) # this controls the speed of the game. low values makes the game slower, and large values makes the game faster.

 pygame.quit()

任何帮助将非常感激。

尝试将输入的密钥保存到变量中，并在事件循环后检查它。 像这样：

#...
lastKey = None
while game_loop:
    for event in pygame.event.get():   # loop through all events
        if event.type == pygame.QUIT:
            game_loop = False # change the game_loop boolean to False to quit.
        if event.type == pygame.KEYDOWN: 
            lastKey = event.key
    #check last entered key
    #lastKey equals "LEFT", "RIGHT", "UP", "DOWN" --> do the required stuff!
    #set x coordinate minus 50 if left was pressed
    if lastKey == pygame.K_LEFT
         x -= 50
    #<add the other statements here>
    #(...)

我建议不要使用那么多 if 语句。一段时间后可能会变得有点混乱。 检查以下问题以使您的代码保持简短：

Python 中 switch 语句的替代品？ https://stackoverflow.com/questions/60208/replacements-for-switch-statement-in-python