从列表中的嵌套字典中删除重复项

快速且非常基本的新手问题。

如果我有如下所示的字典列表：

L = []
L.append({"value1": value1, "value2": value2, "value3": value3, "value4": value4})

假设存在多个条目，其中 value3 和 value4 与其他嵌套字典相同。我如何快速轻松地找到并删除那些重复的词典。

维持秩序并不重要。

Thanks.

EDIT:

如果有五个输入，如下所示：

L = [{"value1": fssd, "value2": dsfds, "value3": abcd, "value4": gk},
    {"value1": asdasd, "value2": asdas, "value3": dafdd, "value4": sdfsdf},
    {"value1": sdfsf, "value2": sdfsdf, "value3": abcd, "value4": gk},
    {"value1": asddas, "value2": asdsa, "value3": abcd, "value4": gk},
    {"value1": asdasd, "value2": dskksks, "value3": ldlsld, "value4": sdlsld}]

输出应如下所示：

L = [{"value1": fssd, "value2": dsfds, "value3": abcd, "value4": gk},
    {"value1": asdasd, "value2": asdas, "value3": dafdd, "value4": sdfsdf},
    {"value1": asdasd, "value2": dskksks, "value3": ldlsld, "value4": sdlsld}

在 Python 2.6 或 3.* 中：

import itertools
import pprint

L = [{"value1": "fssd", "value2": "dsfds", "value3": "abcd", "value4": "gk"},
    {"value1": "asdasd", "value2": "asdas", "value3": "dafdd", "value4": "sdfsdf"},
    {"value1": "sdfsf", "value2": "sdfsdf", "value3": "abcd", "value4": "gk"},
    {"value1": "asddas", "value2": "asdsa", "value3": "abcd", "value4": "gk"},
    {"value1": "asdasd", "value2": "dskksks", "value3": "ldlsld", "value4": "sdlsld"}]

getvals = operator.itemgetter('value3', 'value4')

L.sort(key=getvals)

result = []
for k, g in itertools.groupby(L, getvals):
    result.append(next(g))

L[:] = result
pprint.pprint(L)

在 Python 2.5 中几乎相同，除了你必须使用g.next()代替next(g)在附录中。