从现有数组创建新结果

如果我有一个如下所示的示例数据，我需要从结果数组中获取 FinalResult 数组：

let result = [{
    type: ['Science'],
    link: "www.educatorsector.com"
  },
  {
    type: ['Sports', 'News'],
    link: "www.skysports-news.com"
  },
  {
    type: ['Sports', 'Science'],
    link: "www.cnn-news.com"
  }];

finalResult = [
{ type : "Science", numberOfLinks : 2 }, 
{ type : "Sports", numberOfLinks : 2 },
{ type : "News", numberOfLinks : 1 }]

orThisFinalResult = [
{ type : "Science", links : ["www.educatorsector.com", "www.cnn-news.com"],
{ type : "Sports", links : ["www.skysports-news.com", "www.cnn-news.com"],
{ type : "News", links : ["www.skysports-news.com"]
 }

您可以使用Array.reduce https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce创建一个对象来计算每个对象的所有链接type;然后使用Object.entries https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/entries将这些值作为数组获取，最后使用Array.map https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map转换为对象数组：

let result = [{
    type: ['Science', 'Business'],
    link: "www.educatorsector.com"
  },
  {
    type: ['Sports', 'News'],
    link: "www.skysports-news.com"
  },
  {
    type: ['Sports', 'Health', 'Science'],
    link: "www.cnn-news.com"
  },
  {
    type: ['Health'],
    link: "www.healthsector.com"
  }
];

let output = Object.entries(result
    .reduce((c, o) => {
      o.type
        .forEach(t => c[t] = (c[t] || 0) + 1);
      return c;
    }, {}))
  .map(([type, numberOfLinks]) => ({
    type,
    numberOfLinks
  }));

console.log(output);