我正在尝试读取包含以下内容的文件:
1.0000000e+01 2.9265380e+03 5.0821200e+02 4.3231640e+01
2.0000000e+01 1.0170240e+04 9.2798610e+02 4.0723180e+01
3.0000000e+01 2.1486260e+04 1.1832420e+03 1.0328000e+01
4.0000000e+01 3.3835080e+04 1.1882285e+03 -9.3307000e+00
5.0000000e+01 4.5250830e+04 1.0899705e+03 -1.0320900e+01
6.0000000e+01 5.5634490e+04 9.8935650e+02 -9.8019000e+00
7.0000000e+01 6.5037960e+04 8.9134700e+02 -9.8000000e+00
但我似乎找不到正确的方法来阅读科学记数法。这是我的代码:
#include <stdio.h>
#include <stdlib.h>
int main()
{
// This is the array to store the input
double time[24], altitude[24], velocity[24], acceleration[24];
double var1, var2, var3, var4;
//This is the pointer declaration for opening a file
FILE * fp = fopen("rocket.txt", "r");
int i = 0;
while(fscanf(fp,"%g %f %f %f", &var1, &var2, &var3, &var4) > 0){
time[i] = var1;
altitude[i] = var2;
velocity[i] = var3;
acceleration[i] = var4;
printf("Time: %f \n", &time[i]);
i++;
}
printf("Time: %f", &time[0]);
fclose(fp);
return(0);
}
我尝试过多种组合%f, %g, %d
尝试打印结果,但我永远无法得到正确的结果。
如果有人能指出我正确的方向,我将不胜感激。