我正在使用 Django 信号，但即使发出一次，它们似乎也会被接收两次。这是我正在使用的代码（这是一个将 Uploadify 与 Django 结合使用的简单包装器）...
# Signal-emitting code... emits whenever a file upload is received
# ----------------------------------------------------------------
upload_recieved = django.dispatch.Signal(providing_args=['data'])
def upload(request, *args, **kwargs):
if request.method == 'POST':
if request.FILES:
print 'sending signal'
upload_recieved.send(sender='uploadify', data=request.FILES['Filedata'])
return HttpResponse('True')
# Signal-receiving code...
# ----------------------------------------------------------------
def upload_received_handler(sender, data, **kwargs):
print 'upload received handler'
print 'connecting signal'
upload_recieved.connect(upload_received_handler)
（我刚刚注意到我的信号拼写错误）
我相信你注意到了那里的打印声明。在控制台上，显示的是这样的：
(server starts)
connecting signal
...
sending signal
upload received handler
upload received handler # << == where is this 2nd one coming from?
127.0.0.1 - - [25/Sep/2009 07:28:22] "POST /uploadify/upload/ HTTP/1.1" 200 -
（同样奇怪的是为什么 Django 在信号被触发后报告页面 POST？）
我以前也遇到过这种情况，这是由于您连接信号的模块被导入了两次。为了确保信号不会连接两次，您可以设置dispatch_uid：
upload_recieved.connect(upload_received_handler, dispatch_uid="some.unique.string.id")
UPDATE它实际上记录在这里：http://code.djangoproject.com/wiki/Signals#Helppost_saveseemstobeemissedtwiceforeachsave http://code.djangoproject.com/wiki/Signals#Helppost_saveseemstobeemittedtwiceforeachsave
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