我在本地计算机中创建了一个私有 MSMQ。我使用以下 C# 代码将消息发送到队列。当我将队列更改为事务性队列时,消息未到达 MSMQ。但是,Send 方法中没有抛出异常。我需要做出什么改变才能使其发挥作用?
using System;
using System.Messaging;
using System.Data;
public partial class _Default : System.Web.UI.Page
{
//Sharing violation resulted from queue being open already for exclusive receive.
MessageQueue helpRequestQueue = new MessageQueue(@".\Private$\MyPrivateQueue", false);
protected void Page_Load(object sender, EventArgs e)
{
bool isTransactionalQueue = false;
if (!System.Messaging.MessageQueue.Exists(@".\Private$\MyPrivateQueue"))
{
System.Messaging.MessageQueue.Create(@".\Private$\MyPrivateQueue", isTransactionalQueue);
}
SendMessage();
GetAllMessages();
}
private void SendMessage()
{
System.Messaging.Message theMessage = new System.Messaging.Message("TimeNow is "+DateTime.Now.ToString());
theMessage.Label = "Lijo " + DateTime.Now.ToString();
theMessage.Priority = System.Messaging.MessagePriority.Normal;
helpRequestQueue.Send(theMessage);
}
private void GetAllMessages()
{
DataTable messageTable = new DataTable();
messageTable.Columns.Add("Label");
messageTable.Columns.Add("Body");
//Set Message Filters
MessagePropertyFilter filter = new MessagePropertyFilter();
filter.ClearAll();
filter.Body = true;
filter.Label = true;
filter.Priority = true;
helpRequestQueue.MessageReadPropertyFilter = filter;
//Get All Messages
System.Messaging.Message[] messages = helpRequestQueue.GetAllMessages();
System.Messaging.XmlMessageFormatter stringFormatter = new System.Messaging.XmlMessageFormatter(new string[] { "System.String" });
for (int index = 0; index < messages.Length; index++)
{
string test = System.Convert.ToString(messages[index].Priority);
messages[index].Formatter = stringFormatter;
messageTable.Rows.Add(new string[] {messages[index].Label,messages[index].Body.ToString() });
}
Gridview1.DataSource = messageTable;
Gridview1.DataBind();
}
private void ReceiveAndProcess()
{
}
}
对于您创建为事务性的队列,您必须使用包含 MessageQueueTransactionType 参数的 Send() 版本。最大的挫败感是它不会像您所看到的那样抛出任何异常或错误,但该消息永远不会显示。
因此,在您的代码中更改:
helpRequestQueue.Send(theMessage);
to
helpRequestQueue.Send(theMessage, MessageQueueTransactionType.Single);
编辑:我的答案只是除大卫之外的另一种方法。
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