我不知道如何开始编写程序。
input = input("Input the text you would like encrypted")
def cipher_text(letter_code):
for i in input:
number_code = ord(i) + 3
letter_code = chr(number_code)
print(letter_code)
def plain_text(letter_code,regular_text):
for i in input:
regular_text = letter_code - 3
print(regular_text)
print("Encrypted text")
cipher_text()
print("Unencrypted text")
plain_text()
抱歉这个问题我不知道如何开始。还请提供建议而不是答案。
从数学上来说，如果我们看到encryption技术在Caesar cipher，那么得到加密信件的公式为：
c = (x+n) mod 26,
where c是加密字母的位值，x是实际字母的位值，n是转变。
同样，对于decrypt每个字母，我们使用下面给出的公式：
c = (x-n) mod 26
您可以使用我的下面的代码来了解如何实现Caesar Cipher:
def encrypt(plain_text, s):
encrypted_text = ''
for i in range(len(plain_text)):
if plain_text[i] == ' ':
encrypted_text = encrypted_text + plain_text[i]
elif plain_text[i].isupper():
encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-65)%26+65)
else:
encrypted_text = encrypted_text + chr((ord(plain_text[i])+s-97)%26+97)
return encrypted_text
def decrypt(encrypt_text, s):
decrypted_text = ''
for i in range(len(encrypt_text)):
if encrypt_text[i] == ' ':
decrypted_text = decrypted_text + encrypt_text[i]
elif encrypt_text[i].isupper():
decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-65)%26+65)
else:
decrypted_text = decrypted_text + chr((ord(encrypt_text[i])-s-97)%26+97)
return decrypted_text
plain_text = input("Input the text you would like encrypted:")
s = int(input("Enter shift:"))
encrypt_text = encrypt(plain_text, s)
print("Encrypted text: {}".format(encrypt_text))
print("Decrypted text: {}".format(decrypt(encrypt_text, s)))
示例输出：
Input the text you would like encrypted:Taj Mahal
Enter shift:3
Encrypted text: Wdm Pdkdo
Decrypted text: Taj Mahal
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