我怎样才能解这个方程
x3 + x - 1 = 0
使用定点迭代？
有没有定点迭代我可以在网上找到代码（尤其是Python）吗？
Using scipy.optimize.fixed_point http://docs.scipy.org/doc/scipy/reference/generated/scipy.optimize.fixed_point.html#scipy-optimize-fixed-point:
import scipy.optimize as optimize
def func(x):
return -x**3+1
# This finds the value of x such that func(x) = x, that is, where
# -x**3 + 1 = x
print(optimize.fixed_point(func,0))
# 0.682327803828
Python 代码定义fixed_point位于 scipy/optimize/minpack.py 中。具体位置取决于在哪里scipy已安装。您可以通过输入找到
In [63]: import scipy.optimize
In [64]: scipy.optimize
Out[64]: <module 'scipy.optimize' from '/usr/lib/python2.6/dist-packages/scipy/optimize/__init__.pyc'>
目前的fixed_point源代码可以通过访问在线找到文档页 https://docs.scipy.org/doc/scipy/reference/generated/scipy.optimize.fixed_point.html#scipy-optimize-fixed-point并单击[source] link.
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