矩阵到数组 C#

这将是转换方阵的最有效方法，例如

  1 2 3 
  4 5 6
  7 8 9 

into

[1 2 3 4 5 6 7 8 9]

in c#

我在做

int[,] array2D = new int[,] { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } };
int[] array1D = new int[9];
int ci=0;

 for (int i = 0; i < 3; i++)
 {
      for (int j = 0; j < 3; j++)
      {
            array1D[ci++] = array2D[i, j]);
      }
 }

LINQ 使这一切变得微不足道。

int[,] array2d = ...;
var array1d = array2d.Cast<int>().ToArray();

否则，你的方法是足够的，但可以概括：

int[,] array2d = ...;
var rows = array2d.GetLength(0);
var cols = array2d.GetLength(1);
var array1d = new int[rows * cols];
var current = 0;
for (int i = 0; i < rows; i++)
{
    for (int j = 0; j < cols; j++)
    {
        array1d[current++] = array2d[i, j];
    }
}

Or even:

int[,] array2d = ...;
var array1d = new int[array2d.GetLength(0) * array2d.GetLength(1)];
var current = 0;
foreach (var value in array2d)
{
    array1d[current++] = value;
}