c# Newtonsoft.Json 常用方法总结

1 实体类的 Json 序列化和反序列化
我们以如下的 Person 类举例，其中包含了常用的数据类型：

public class Person
{
 public int ID { get; set; }
 
 public string Name { get; set; }
 
 public DateTime Birthday { get; set; }
 
 public bool IsVIP { get; set; }
  
 public float Account { get; set; }
 
 public string[] Favorites { get; set; }
  
 public string Remark { get; set; }
}

创建一个 Person 实例：

Person person = new Person
{
 ID = 1,
 Name = "张三",
 Birthday = DateTime.Parse("2000-01-02"),
 IsVIP = true,
 Account = 12.34f,
 Favorites = new string[] { "吃饭", "睡觉" }
};

1.1 Json 序列化
返回不缩进的 Json 字符串

JsonConvert.SerializeObject(person);
 
{"ID":1,"Name":"张三","Birthday":"2000-01-02T00:00:00","IsVIP":true,"Account":12.34,"Favorites":["吃饭","睡觉"],"Remark":null}

返回缩进的 Json 字符串

JsonConvert.SerializeObject(person, Formatting.Indented);
 
{
 "ID": 1,
 "Name": "张三",
 "Birthday": "2000-01-02T00:00:00",
 "IsVIP": true,
 "Account": 12.34,
 "Favorites": [
  "吃饭",
  "睡觉"
 ],
 "Remark": null
}
 

1.2 将不缩进的 JSON 字符串转成缩进形式

private string JsonIndentation(string str)
{
 //string str = JsonConvert.SerializeObject(entity);
 JsonSerializer serializer = new JsonSerializer();
 TextReader tr = new StringReader(str);
 JsonTextReader jtr = new JsonTextReader(tr);
 object obj = serializer.Deserialize(jtr);
 if (obj != null)
 {
  StringWriter textWriter = new StringWriter();
  JsonTextWriter jsonWriter = new JsonTextWriter(textWriter)
  {
   Formatting = Formatting.Indented,
   Indentation = 4,
   IndentChar = ' '
  };
  serializer.Serialize(jsonWriter, obj);
  return textWriter.ToString();
 }
 else
 {
  return str;
 }
}

或者：

private string JsonIndentation(string json)
{
 JObject obj = JObject.Parse(json);
 return obj.ToString();
}

1.3 其他设置

JsonSerializerSettings settings = new JsonSerializerSettings();
// 设置日期格式
settings.DateFormatString = "yyyy-MM-dd";
// 忽略空值
settings.NullValueHandling = NullValueHandling.Ignore;
// 缩进
settings.Formatting = Formatting.Indented;
 
JsonConvert.SerializeObject(person, settings);

返回：

{
 "ID": 1,
 "Name": "张三",
 "Birthday": "2000-01-02",
 "IsVIP": true,
 "Account": 12.34,
 "Favorites": [
 "吃饭",
 "睡觉"
 ]
}
 

1.4 Json 反序列化

JsonConvert.DeserializeObject<Person>(json);

2 JObject 使用

2.1 创建c#教程对象

JObject obj = new JObject(); obj.Add("ID", 1); obj.Add("Name", "张三"); obj.Add("Birthday", DateTime.Parse("2000-01-02")); obj.Add("IsVIP", true); obj.Add("Account", 12.34f); // 创建数组 JArray array = new JArray(); array.Add(new JValue("吃饭")); array.Add(new JValue("睡觉")); obj.Add("Favorites", array); obj.Add("Remark", null);

2.2 JObject 中添加数组
上例中的代码可以简化为：

JArray array = new JArray("吃饭", "睡觉");
 

2.3 从 Json 字符串创建 JObject

string json = "{\"ID\":1,\"Name\":\"张三\",\"Birthday\":\"2000-01-02T00:00:00\",\"IsVIP\":true,\"Account\":12.34,\"Favorites\":[\"吃饭\",\"睡觉\"],\"Remark\":null}";
 
JObject obj = JObject.Parse(json);
 

2.4 从 Entity 创建 JObject
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JObject obj = JObject.FromObject(person);
用匿名对象创建 JObject

JObject obj = JObject.FromObject(new { name = "jack", age = 18 });
 


//显示
{
 "name": "jack",
 "age": 18
}

用初始化器

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JObject obj = new JObject()
{
{ “name”, “jack” },
{ “age”, 18 }
};

2.5 获取值

int id;
if (obj["ID"] != null)
 id = obj["ID"].Value<int>();
 

2.6 获取数组
Newtonsoft.Json.Linq 不支持直接获取数组，但是可以获取 List，然后再转化为数组。

string[] favorites;
if (obj["Favorites"] != null)
 favorites = obj["Favorites"].Value<List<string>>().ToArray();

以上就是c# Newtonsoft.Json 常用方法总结的详细内容