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Reference – Password Validation 1个
我在网上看到了以下正则表达式.
(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$
它只在字符串中有效：
* contain at least (1) upper case letter
* contain at least (1) lower case letter
* contain at least (1) number or special character
* contain at least (8) characters in length
我想知道如何转换这个正则表达式,以便它检查字符串
* contain at least (2) upper case letter
* contain at least (2) lower case letter
* contain at least (2) digits
* contain at least (2) special character
* contain at least (8) characters in length
好吧,如果它包含至少2个上,下,数字和特殊字符,那么我不会
需要8个字符的长度.
特殊字符包括：
`~!@#$%^&*()_-+=[]\|{};:'”.,/<>?
