如何修改下面自定义 QMessageBox 的代码才能知道用户是否单击“是”或“否”?
from PySide import QtGui, QtCore
# Create a somewhat regular QMessageBox
msgBox = QtGui.QMessageBox( QtGui.QMessageBox.Question, "My title", "My text.", QtGui.QMessageBox.Yes | QtGui.QMessageBox.No )
# Get the layout
question_layout = msgBox.layout()
# Additional widgets to add to the QMessageBox
qlabel_workspace_project = QtGui.QLabel('Some random data window:')
qtextedit_workspace_project = QtGui.QTextEdit()
qtextedit_workspace_project.setReadOnly(True)
# Add the new widgets
question_layout.addWidget(qlabel_workspace_project,question_layout.rowCount(), 0, 1, question_layout.columnCount() )
question_layout.addWidget(qtextedit_workspace_project,question_layout.rowCount(), 0, 1, question_layout.columnCount() )
# Show widget
msgBox.show()
代替show
你应该使用exec_
方法,所有小部件都继承自QDialog
have:
http://doc.qt.io/qt-4.8/qmessagebox.html#exec
此方法会阻塞,直到 msgbox 关闭并返回结果:
result = msgBox.exec_()
if result == QtGui.QMessageBox.Yes:
# do yes-action
else:
# do no-action
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