Python：同行if...else...详细教程

我最近为游戏Apple Clicker写成就系统，加上后整个程序的代码竟然超过2200行，窗口启动时间也很慢，主要是if...else...使用的太多。于是查了查缩短代码的方法，总结如下：

示例一

if get > 10 :
	num = 1
else:
	num = 0

可以简化为：

num = 1 if param > 10 else 0 

示例二

if param > 10 :
	num = 1
elif param == 10:
	num = 2
else:
	num = 0

可以简化为：

num = 1 if param > 10  else 2 if param == 10 else 0 

多行语句可以用分号“; ”隔开。

示例三

这是成就系统的一小部分：

if apple_amount >= 1 and achievement_1_get == 0:
-            achievement_1_on = 1
-        else:
-            achievement_1_on = 0
-        if apple_amount >= 100 and achievement_2_get == 0:
-            achievement_2_on = 1
-        else:
-            achievement_2_on = 0
-        if apple_amount >= 1000 and achievement_3_get == 0:
-            achievement_3_on = 1
-        else:
-            achievement_3_on = 0
-        if apple_amount >= 10000 and achievement_4_get == 0:
-            achievement_4_on = 1
-        else:
-            achievement_4_on = 0
-        if apple_amount >= 100000 and achievement_5_get == 0:
-            achievement_5_on = 1
-        else:
-            achievement_5_on = 0
-        if apple_amount >= 1000000 and achievement_6_get == 0:
-            achievement_6_on = 1
-        else:
-            achievement_6_on = 0
-        if apple_amount >= 10000000 and achievement_7_get == 0:
-            achievement_7_on = 1
-        else:
-            achievement_7_on = 0
-        if apple_amount >= 100000000 and achievement_8_get == 0:
-            achievement_8_on = 1
-        else:
-            achievement_8_on = 0
-        if apple_amount >= 1000000000 and achievement_9_get == 0:
-            achievement_9_on = 1
-        else:
-            achievement_9_on = 0
-        if apple_amount >= 10000000000 and achievement_10_get == 0:
-            achievement_10_on = 1
-        else:
-            achievement_10_on = 0
-        if apple_amount >= 100000000000 and achievement_31_get == 0:
-            achievement_31_on = 1
-        else:
-            achievement_31_on = 0
-        if apple_amount >= 1000000000000 and achievement_32_get == 0:
-            achievement_32_on = 1
-        else:
-            achievement_32_on = 0
-        if apple_amount >= 10000000000000 and achievement_33_get == 0:
-            achievement_33_on = 1
-        else:
-            achievement_33_on = 0
-        if apple_amount >= 100000000000000 and achievement_34_get == 0:
-            achievement_34_on = 1
-        else:
-            achievement_34_on = 0
-        if apple_amount >= 1000000000000000 and achievement_35_get == 0:
-            achievement_35_on = 1
-        else:
-            achievement_35_on = 0

 修改后变成这样：

achievement_1_on = 1 if apple_amount >= 1 and achievement_1_get == 0 else 0
achievement_2_on = 1 if apple_amount >= 100 and achievement_2_get == 0 else 0
achievement_3_on = 1 if apple_amount >= 1000 and achievement_3_get == 0 else 0
achievement_4_on = 1 if apple_amount >= 10000 and achievement_4_get == 0 else 0
achievement_5_on = 1 if apple_amount >= 100000 and achievement_5_get == 0 else 0
achievement_6_on = 1 if apple_amount >= 1000000 and achievement_6_get == 0 else 0
achievement_7_on = 1 if apple_amount >= 10000000 and achievement_7_get == 0 else 0
achievement_8_on = 1 if apple_amount >= 100000000 and achievement_8_get == 0 else 0
achievement_9_on = 1 if apple_amount >= 1000000000 and achievement_9_get == 0 else 0
achievement_10_on = 1 if apple_amount >= 10000000000 and achievement_10_get == 0 else 0
achievement_31_on = 1 if apple_amount >= 100000000000 and achievement_31_get == 0 else 0
achievement_32_on = 1 if apple_amount >= 1000000000000 and achievement_32_get == 0 else 0
achievement_33_on = 1 if apple_amount >= 10000000000000 and achievement_33_get == 0 else 0
achievement_34_on = 1 if apple_amount >= 100000000000000 and achievement_34_get == 0 else 0
achievement_35_on = 1 if apple_amount >= 1000000000000000 and achievement_35_get == 0 else 0

既简洁、易读又省行数，初学者可能比较难理解，但用一用就熟悉了。

把所有if...else...修改后，整个程序的长度只剩1600多行了，效果还是很显著的。

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