我正在使用 purrr 和 broom 包来生成一系列 glm,并构建一个包含模型信息的表,以便我可以对它们进行比较。
当我从 purrr 调用地图函数时,代码失败。我认为问题与 mutate 和 map 的组合有关。我想生成一个表,其中每个 glm 为一行,glm 组件为列。
数据和代码
library(broom)
library(tidyverse)
# Produce a dummy dataset
set.seed(123)
dummy <- tibble(ID = 1:50,
A = sample(x = 1:200, size = 50, replace = T),
B = as.factor(sample(x = c("day", "night"), size = 50, replace = T)),
C = as.factor(sample(x = c("blue", "red", "green"), size = 50, replace = T)))
# Nest the data
nested <- dummy %>% select(-ID) %>% nest()
# Define a function for a generalized linear model with a poisson family
mod_f <- function(x, df = nested) {glm(formula = as.formula(x), family = poisson, data = df)}
# Make a list of formulas as a column in a new dataframe
# A is our response variable that we try to predict using B and C
formulas <- c("A ~ 1", "A ~ B", "A ~ C", "A ~ B + C")
tbl <- tibble(forms = formulas)
# Fit the glm's using each of the formulas from the formulas vector
tbl_2 <- tbl %>% mutate(mods = map(formulas, mod_f))
#gla = mods %>% map(glance),
#tid = mods %>% map(tidy),
#aug = mods %>% map(augment),
#AIC = gla %>% map_dbl("AIC"))
ERROR
mutate_impl(.data,dots) 中的错误:评估错误:找不到对象“A”