我试图理解如何数字::toString(x) https://262.ecma-international.org/11.0/#sec-numeric-types-number-tostring抽象操作有效。
据我所知，其要点似乎是非常大（n > 21）和非常小（n
String(1.5e22) // => "1.5+22"
...其他所有内容均以十进制表示法（步骤 6-9）
String(1.5e1) // => "15"
这是第五步：
- Otherwise, let
n, k, and s be integers such that k ≥ 1, 10k - 1 ≤ s < 10k, the Number value for ℝ(s) × 10ℝℝ(n) - ℝ(k) is x, and k is as small as possible. Note that k is the number of digits in the decimal representation of s, that s is not divisible by 10ℝ, and that the least significant digit of s is not necessarily uniquely determined by these criteria.
-
为什么需要步骤 5 中的约束？
Namely, that k is as small as possible, 10k - 1 ≤ s < 10k and s is not divisible by 10ℝ.
-
的价值观如何n and k found?
For the number 1.5e1, the smallest k for 10k - 1 ≤ s < 10k and k ≥ 1 to both be true is 2, which would mean n = 2. But this doesn't seem to be correct, since it takes me to step 6 (as k ≤ n ≤ 21), which doesn't produce the string "15".
-
步骤 6 对应什么用例？
- If
k ≤ n ≤ 21, return the string-concatenation of:
- 的代码单元
k的十进制表示形式的数字s（按顺序，没有前导零）
-
n - k代码单元 0x0030（数字零）的出现次数
None
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