如何在集成测试中传递授权令牌标头？

A 相关问题 https://stackoverflow.com/questions/12041091/ror-testing-an-action-that-uses-http-token-authentication意味着我可以使用令牌身份验证来测试请求，在我的 集成测试，如下：

get "/v1/sites", nil, :authorization => "foo"
assert_response :success

由于某种原因，标头无法到达我的应用程序：

get "/v1/sites", nil, :authorization => "foo"
assert_match response.headers, /foo/

Expected {"X-Frame-Options"=>"SAMEORIGIN", "X-XSS-Protection"=>"1; mode=block", "X-Content-Type-Options"=>"nosniff", "X-UA-Compatible"=>"chrome=1", "WWW-Authenticate"=>"Token realm=\"Application\"", "Content-Type"=>"text/html; charset=utf-8", "Cache-Control"=>"no-cache", "X-Request-Id"=>"23915302-9cfe-424d-86fe-5d60bc0d6b2c", "X-Runtime"=>"0.054857", "Content-Length"=>"27"} to match /foo/.

授权标头未通过，我可以在放置时确认throw response.headers在控制器中。当我 测试例如卷曲，我do看到标题通过。在那里我 甚至可以设置令牌并获取访问权限。相关代码来自 控制器是：

module V1
  class SitesController < ApplicationController
    before_filter :restrict_access, :only => :index

    def index
      head :success
    end

    private
    def restrict_access
      authenticate_or_request_with_http_token do |token, options|
        token == "foo"
      end
    end
  end 
end

这是最迷你的，在 Rails 4 上，使用Rails-API https://github.com/rails-api/rails-api

作为参考，这里是中间件堆栈，它比大多数默认的 Rails 应用程序要精简得多。

use ActionDispatch::Static
use Rack::Lock
use #<ActiveSupport::Cache::Strategy::LocalCache::Middleware:0x992cd28>
use Rack::Runtime
use ActionDispatch::RequestId
use Rails::Rack::Logger
use ActionDispatch::ShowExceptions
use ActionDispatch::DebugExceptions
use ActionDispatch::RemoteIp
use ActionDispatch::Reloader
use ActionDispatch::Callbacks
use ActiveRecord::Migration::CheckPending
use ActiveRecord::ConnectionAdapters::ConnectionManagement
use ActiveRecord::QueryCache
use ActionDispatch::ParamsParser
use Rack::Head
use Rack::ConditionalGet
use Rack::ETag
run MyApp::Application.routes

仅供参考。一切都是对的，我只是愚蠢而已测试错误的东西调试时：

assert_match response.headers, /foo/

显然是假的，因为这是response。正确的是测试request

get "/v1/sites", nil, :authorization => %{Token token="foo"}
assert_includes request.headers["HTTP_AUTHORIZATION"], "foo"

这一切都很好。