这是我的完整代码 https://gist.github.com/bd44e03153a499a0de62,我自定义异常,例如:
class StdErr : public std::exception {
public:
str msg;
StdErr(str msg) { this->msg = msg; };
virtual const char *what() const override {
return this->msg.c_str();
};
};
并像这样继承它:
class ShErr : public StdErr {
public:
ShErr(str m) : StdErr(m) { }
};
并像这样使用它们:
int main(int argc, char **argv) {
throw ro_err::ShErr("sh err");
return (0);
};
它提高了looser throw specifier for ‘virtual const char* ro_err::StdErr::what() const’
,我有以下问题:
从c++11开始what()
is noexcept。您尚未将其声明为noexcept。这就是“宽松的投掷说明符”告诉您的。看http://en.cppreference.com/w/cpp/error/exception/what http://en.cppreference.com/w/cpp/error/exception/what.
IE。声明它就像
virtual const char *what() const noexcept override
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