strtok用法详解

字符串操作函数strtok用法：
char* strtok（char* src，char* split）；
函数参数：
src：被分割的字符串
split：分割的标志，分割字符串
函数返回值：
成功：返回被分割出的字符串
失败：NULL
分割字符串后原串src变成第一次分割成功后分割出的字符串。
（1）首次分割 ： char* p = strtok(src,split);
（2）往后继续分割：
char* p1 = strtok（NULL，split）；
char* p2 = strtok（NULL，split）；
…

在完整功能中的用法实例

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <fcntl.h>
#define INFO_SIZE 128
char* getText(char *src)
{
	if(!src)
	{
		return NULL;
	}
    /*strtok用法如下：*/
	char *p = strtok(src,"=");
	p = strtok(NULL,"=");
	return p;
}


int main()
{
	FILE* fp = NULL;
	fp = fopen("1.txt","r");
	if(!fp)
	{
		return -1;
	}

	char* p = NULL;
	char recv[INFO_SIZE] = {0};
	char data[20] = {0};
	char *name = NULL;
	char *age  = NULL;
	char *phone = NULL;
	char recv_next[INFO_SIZE] = {0};
	printf("please input :\n");
	fgets(data,INFO_SIZE,stdin);
	data[strlen(data) - 1] = '\0';
	if(strstr(data,"name") != NULL)
	{
		p = getText(data);
		if(!p)
		{
			return -1;
		}

		printf("p = %s\n",p);
		while(fgets(recv,INFO_SIZE,fp) != NULL && recv[0] != '\n')
		{
			if(strncmp(recv,p,strlen(p)) == 0 && recv[strlen(p)] == ',')
			{
				name = strtok(recv,",");
				age = strtok(NULL,",");
				phone = strtok(NULL,",");
				printf("recv = %s\n",recv);
				printf("output:age = %s,phone = %s\n",age,phone);
			}

			memset(recv,0,INFO_SIZE);
		}

	}

	else if(strstr(data,"age") != NULL)
	{
		p = getText(data);
		if(!p)
		{
			return -1;
		}

		while(fgets(recv,INFO_SIZE,fp) != NULL && recv[0]!='\n')
		{
			strcpy(recv_next,recv);
			name = strtok(recv_next,",");
			age = strtok(NULL,",");
			phone = strtok(NULL,",");
			if(strncmp(age,p,strlen(p)) == 0 && recv[strlen(name)  + 1 +  strlen(age)] == ',')
			{
				//if(strncmp(age,p,strlen(p)) == 0)
				//{
				name = strtok(recv,",");
				age = strtok(NULL,",");
				phone = strtok(NULL,",");
				printf("output : name = %s,phone = %s\n",age,phone);
			}

			memset(recv,0,INFO_SIZE);
			memset(recv_next,0,INFO_SIZE);
	
			}	
		}

		else
		{
			return -1;
		}

		fclose(fp);



		return 0;
	}

                     ![文件1.txt内容](https://img-blog.csdnimg.cn/2e2246365a0948f1869c66ac905f34cd.png#pic_center)