SQL：递归路径

是否可以在 SQL 中创建“树解析器”？

我有一张桌子：

ID Name Parent
1  a
2  b    1
3  c    1
4  d    3

现在我想要一个返回的 SQL 查询：

ID   PATH
1    /a
2    /a/b
3    /a/c
4    /a/c/d

这可以用 SQL 实现吗？这会让我的很多事情变得更容易。任何帮助将不胜感激！

在 sql server 2005 及更高版本中使用 CTE，这是我必须执行此操作的代码片段：

WITH Paths([Level], [FullPath], [ID]) AS 
(
    SELECT 
        0 AS [Level], 
        Name AS FullPath, 
        ID
    FROM dbo.Entity
    WHERE (ParentEntityID IS NULL)

    UNION ALL

    SELECT 
        p.[Level] + 1 AS [Level], 
        CASE RIGHT(p.[FullPath], 1) 
        WHEN '\' THEN p.[FullPath] + c.[Name] 
        ELSE p.[FullPath] + '\' + c.[Name] 
    END AS FullPath, 
    c.ID
    FROM dbo.Entity AS c 
    INNER JOIN Paths AS p ON p.ID = c.ParentEntityID
)
SELECT [FullPath], [ID]
FROM Paths